Python Split() Without Removing the Delimiter

Python split() without removing the delimiter

d = ">"
for line in all_lines:
    s =  [e+d for e in line.split(d) if e]

Python String Split on pattern without removing delimiter

You can also use a look ahead regex:

import re
re.split(r'.(?=123 my)', my_str)
=>
['123 my string is long',
 '123 my string is very long',
 '123 my string is so long']

Splitting on regex without removing delimiters

You can use re.findall with regex .*?[.!\?]; the lazy quantifier *? makes sure each pattern matches up to the specific delimiter you want to match on:

import re

s = """You! Are you Tom? I am Danny."""
re.findall('.*?[.!\?]', s)
# ['You!', ' Are you Tom?', ' I am Danny.']

split string without removal of delimiter in python

You could use re.split with forward lookahead:

import re
re.split('\s(?=\d\s)',content)

resulting in:

['This', '1 string is very big', '2 i need to split it', '3 into paragraph wise.', '4 But this string', '5 not a formated string.']

This splits on spaces -- but only those which are immediately followed by a digit then another space.

Python split() without removing the delimiter in a list

works this code :)

lista = ['int32','decimal(14)','int(32)','string','date','decimal(27,2)','decimal(17,2)']
lst = []
for i in lista:
    x= (i.find('('))
    if(x != -1):
        lst.append(i[0:x])
        lst.append(i[x::])
    else:
        lst.append(i)
print(lst)

How to split a string without removing the delimiter?

You need to add \d+ inside your regular expression, like so:

(__label__\d+:)

This also allows you to capture all numericals rather than having to list all possible values...

In Python, how do I split a string and keep the separators?

The docs of re.split mention:

Split string by the occurrences of pattern. If capturing
parentheses are used in pattern, then the text of all groups in the
pattern are also returned as part of the resulting list.

So you just need to wrap your separator with a capturing group:

>>> re.split('(\W)', 'foo/bar spam\neggs')
['foo', '/', 'bar', ' ', 'spam', '\n', 'eggs']

Python: Split string without losing split character

If you want to do this in a single line:

string = "HELLO.WORLD.AGAIN."
pattern = "."
result = string.replace(pattern, f" {pattern} ").split(" ")
# if you want to omit the last element because of the punctuation at the end of the string uncomment this
# result = result[:-1] 

Split string without losing delimiter (and its count)

Try with re.split with the expression of (\s+):

>>> import re
>>> string = "This            is a                      test."
>>> re.split(r'(\s+)', string)
['This', '            ', 'is', ' ', 'a', '                      ', 'test.']
>>> 

Regex101 example.

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