How do I convert a datetime to date?
Use the date()
method:
datetime.datetime.now().date()
Convert DateTime to Date in ES6
I also don't like using libraries for every tasks that can be easily done without library.Here are some of the in-build JS methods that you must give a try:
let date1=new Date("2020-06-16T02:55:08.151437Z").toDateString()console.log(date1)
let date2=new Date("2020-06-16T02:55:08.151437Z").toUTCString()console.log(date2)
let date3=new Date("2020-06-16T02:55:08.151437Z").toLocaleDateString()console.log(date3)
let date4=new Date("2020-06-16T02:55:08.151437Z").toLocaleDateString('en-US', {month: '2-digit',day: '2-digit',year: 'numeric'})console.log(date4)
let date5=new Date("2020-06-16T02:55:08.151437Z").toString()console.log(date5)
let date6=new Date("2020-06-16T02:55:08.151437Z").toLocaleString()console.log(date6)
How to convert a datetime to date in R, WITHOUT rounding the day?
Do your input dates include a timezone specification? If not, they are ambiguous and the rounding may be right or it may be wrong. If they do include a timezone specification, the lubridate
package should handle them correctly.
I would advise against using tz = Sys.timezone()
because that would make the interaction between input data and algorithm dependent on geography if your inputs don't include a timezone specification, so what works for you might not work for a different user in a different location.
convert datetime to date format dd/mm/yyyy
DateTime dt = DateTime.ParseExact(yourObject.ToString(), "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);
string s = dt.ToString("dd/M/yyyy", CultureInfo.InvariantCulture);
Convert string Jun 1 2005 1:33PM into datetime
datetime.strptime
parses an input string in the user-specified format into a timezone-naive datetime
object:
>>> from datetime import datetime
>>> datetime.strptime('Jun 1 2005 1:33PM', '%b %d %Y %I:%M%p')
datetime.datetime(2005, 6, 1, 13, 33)
To obtain a date
object using an existing datetime
object, convert it using .date()
:
>>> datetime.strptime('Jun 1 2005', '%b %d %Y').date()
date(2005, 6, 1)
Links:
strptime
docs: Python 2, Python 3strptime
/strftime
format string docs: Python 2, Python 3strftime.org format string cheatsheet
Notes:
strptime
= "string parse time"strftime
= "string format time"
How to return only the Date from a SQL Server DateTime datatype
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @your_date))
for example
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
gives me
2008-09-22 00:00:00.000
Pros:
- No varchar<->datetime conversions required
- No need to think about locale
Converting DateTime Format to date
Use SimpleDateFormat class and you can convert it into any format you want.
String dateStr = "2014-01-09T09:33:20+0530";
SimpleDateFormat curFormater = new SimpleDateFormat("yyyy-MM-dd");
Date dateObj = curFormater.parse(dateStr);
String newDateStr = curFormater.format(dateObj);
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