How do I check if there are duplicates in a flat list?
Use set()
to remove duplicates if all values are hashable:
>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
True
How to check if a list contains duplicate items?
As said by Jkdc, convert it to a set and compare the length
lst = ["1","2","3","3","4"]
if len(set(lst)) == len(lst):
print("success")
else:
print("duplicate found")
C# Determine Duplicate in List
Unless I'm missing something, then you should be able to get away with something simple using Distinct()
. Granted it won't be the most complex implementation you could come up with, but it will tell you if any duplicates get removed:
var list = new List<string>();
// Fill the list
if(list.Count != list.Distinct().Count())
{
// Duplicates exist
}
How to find duplicates in a list of list of objects in java
Actually, you have:
List<List<String>> compositeKeyValues;
Lists are equal if they have the same elements in the same order - like your example.
Finding duplicate inner Lists is no different finding duplicates of other simpler types.
Here's one way:
List<List<String>> duplicates = compositeKeyValues.stream()
.collect(Collectors.groupingBy(Function.identity(), Collectors.counting()))
.entrySet().stream()
.filter(e -> e.getValue().intValue() > 1)
.map(Map.Entry::getKey)
.collect(Collectors.toList());
This code will work even if you leave the type of the List as List<Object>
, except the result would also have type List<Object>
. However, it's recommended, and more useful, to use a more specific type List<List<String>>
.
R - Finding duplicates in list entries
You can unlist
first:
unlisted <- unlist(examplelist)
unlisted[duplicated(unlisted)]
# b1 c1 c2
# "red" "black" "green"
unlisted[!duplicated(unlisted)]
# a1 a2 a3 b2 b3 c3
# "blue" "red" "yellow" "black" "green" "brown"
If you only want the vector (without the names), use unname
:
unlisted <- unname(unlist(examplelist))
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