How to Prepare Statement for Update Query

Update SQL database with preparedStatement in Java

The code is now working. Thanks for Prashant for his answer. Once slightly adapted it worked well

String query = ("UPDATE TB01 SET BLADETYPE=?,STARTT1=?,AIRT1=?,FOAMT1=?,SCT1=?,FINISHT1=? WHERE SERIAL=?");
try (PreparedStatement pstmt = conn.prepareStatement(query)) {
    pstmt.setString(7, bladeSerial);
    pstmt.setString(1, itemText);
    pstmt.setString(2, String.valueOf(startTime1));
    pstmt.setString(3, String.valueOf(airTime1));
    pstmt.setString(4, String.valueOf(foamTime1));
    pstmt.setString(5, String.valueOf(scTime1));
    pstmt.setString(6, String.valueOf(finishTime1));
    pstmt.executeUpdate();
                                                             }
catch (SQLException ex) {
    // Exception handling
    Logger.getLogger(FormTwo1.class.getName()).log(Level.SEVERE, null, ex);
                          }

Note as SERIAL had moved to the end of the string, the order also needed changing on the setString commands.

php update query using prepared statement not working

Add $stmt->close(); before your next mysqli interaction.

if(sendMail($email,$verify_key)) {  // send mail first then update DB
    $stmt->close();
    $query = " UPDATE `signup` SET `name`=?,`password`=?,`verify_key`=? WHERE `email`=? ";

or you might just always want to execute the close after you're finished with your previous mysql interaction.

e.g.:

$query = " SELECT active FROM signup WHERE email=?";
$stmt = $conn->prepare($query);
$stmt->bind_param("s",$email);
$stmt->execute();
$stmt->bind_result($dbactive);
$stmt->close();

and remove the $stmt->close(); from the if. I've never seen official documentation on this but I've seen other threads were this was an underlying issue. The manual page itself actual almost states the opposite:

So, while explicitly closing open connections and freeing result sets is optional, doing so is recommended.

that is optional is false (... in my experience, I also primarily use PDO).

How to prepare statement for update query?

An UPDATE works the same as an insert or select. Just replace all the variables with ?.

$sql = "UPDATE Applicant SET phone_number=?, street_name=?, city=?, county=?, zip_code=?, day_date=?, month_date=?, year_date=? WHERE account_id=?";

$stmt = $db_usag->prepare($sql);

// This assumes the date and account_id parameters are integers `d` and the rest are strings `s`
// So that's 5 consecutive string params and then 4 integer params

$stmt->bind_param('sssssdddd', $phone_number, $street_name, $city, $county, $zip_code, $day_date, $month_date, $year_date, $account_id);
$stmt->execute();

if ($stmt->error) {
  echo "FAILURE!!! " . $stmt->error;
}
else echo "Updated {$stmt->affected_rows} rows";

$stmt->close();

PHP UPDATE prepared statement

$stmt = $this->mysqli->prepare("UPDATE datadump SET content=? WHERE id=?");
/* BK: always check whether the prepare() succeeded */
if ($stmt === false) {
  trigger_error($this->mysqli->error, E_USER_ERROR);
  return;
}
$id = 1;
/* Bind our params */
/* BK: variables must be bound in the same order as the params in your SQL.
 * Some people prefer PDO because it supports named parameter. */
$stmt->bind_param('si', $content, $id);

/* Set our params */
/* BK: No need to use escaping when using parameters, in fact, you must not, 
 * because you'll get literal '\' characters in your content. */
$content = $_POST['content'] ?: '';

/* Execute the prepared Statement */
$status = $stmt->execute();
/* BK: always check whether the execute() succeeded */
if ($status === false) {
  trigger_error($stmt->error, E_USER_ERROR);
}
printf("%d Row inserted.\n", $stmt->affected_rows);

Re your questions:

I get a message from my script saying 0 Rows Inserted

This is because you reversed the order of parameters when you bound them. So you're searching the id column for the numeric value of your $content, which is probably interpreted as 0. So the UPDATE's WHERE clause matches zero rows.

do I need to declare all the fields or is it ok to just update one field??

It's okay to set just one column in an UPDATE statement. Other columns will not be changed.

Multiple update query in single prepare execute statement mysql

Try this. you have to pass comma separated list of the ids you have to update as the first argument of your procedure. Hope this helps.

DELIMITER $$

CREATE PROCEDURE proc_name(IN strIDs VARCHAR(255))
BEGIN
  DECLARE strLen    INT DEFAULT 0;
  DECLARE SubStrLen INT DEFAULT 0;

  IF strIDs IS NULL THEN
    SET strIDs = '';
  END IF;

do_this:
  LOOP
    SET strLen = LENGTH(strIDs);

    update tableName
    set column2 = 'a', column3 = 'b' 
    where column1 = SUBSTRING_INDEX(strIDs, ',', 1);

    SET SubStrLen = LENGTH(SUBSTRING_INDEX(strIDs, ',', 1));
    SET strIDs = MID(strIDs, SubStrLen, strLen);

    IF strIDs = NULL THEN
      LEAVE do_this;
    END IF;
  END LOOP do_this;

END
$$

DELIMITER ;

UPDATE query using prepared statement with multiple WHERE conditions

In MySql you can do tuples comparasion.

So you can do something like this

UPDATE bla 
SET x=123
WHERE (x,y) in ((12,13),(13,13),(25,23),(37,33),(39,13),(44,23),(54,33),(84,23),(94,23),(99,33))

How to UPDATE in database using mysqli prepared statement?

For procedural way

$query = "UPDATE `crew_info` SET `updated_photo` = ? WHERE `id` = ?";
$stmt = mysqli_prepare($conn, $query);
// you should use i instead of s for id
mysqli_stmt_bind_param($stmt, 'si', $imageData, $_GET['id']);
mysqli_stmt_execute($stmt);

Try this out in object-oriented style

$query = "UPDATE `crew_info` SET `updated_photo` = ? WHERE `id` = ?";
$stmt = $conn->prepare($query);
$stmt->bind_param("si", $imageData, $_GET['id']);
$stmt->execute();

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