How to I Retrieve Last Part of Url and Use It in HTML

Last segment of URL with JavaScript

You can also use the lastIndexOf() function to locate the last occurrence of the / character in your URL, then the substring() function to return the substring starting from that location:

console.log(this.href.substring(this.href.lastIndexOf('/') + 1));

That way, you'll avoid creating an array containing all your URL segments, as split() does.

Get last part of the url

OK, so it appears no one here attempted to try the solution here before posting.

First things first cheeks.... This is a tricky ID to find (You have to escape the periods). The label is also not part of the internal html where ID is cheeks..., so we need to find the adjacent element and look the a anchor tag you're looking for.

Here's the code:

$(document).ready(function() {
    $('#Cheeks\\.\\.\\.').next('label').find('a').each(function(){
          var lasturl = $(this).attr('href');
          var urlsplit = lasturl.split("/");
         console.log(urlsplit);
          var finalvar = urlsplit.pop();
        console.log('Adding class: ' + finalvar);
          $(this).addClass(finalvar);
    });
});

And here is a working jsfiddle with the solution.

Display the last part of URL javascript?

<script type="text/javascript">

var segment_str = window.location.pathname; // return segment1/segment2/segment3/segment4
var segment_array = segment_str.split( '/' );
var last_segment = segment_array.pop();
document.write(last_segment); // alerts segment4

</script>

JsFiddle: http://jsfiddle.net/HNMV3/1/

Javascript to grab last part of the document.URL?

You could simply use .split() on window.location.href, and grab the last entry.

Example:

var lastPart = window.location.href.split("/").pop();

jQuery get last part of URL

var str="url";

str.split("/")[3]

you can use split

URL - Get last part in PHP

use following

<?php
    $link = $_SERVER['PHP_SELF'];
    $link_array = explode('/',$link);
    echo $page = end($link_array);
?>

pcre. How to get last part of url

The preg_replace only replaces what you have it find. In this case product-123.html. So you're replacing /product-123.html with product-123.html and the https://example.com.ua/part1/part2/part3 remains untouched.

To replace everything and only keep the match you'd do

echo 
preg_replace('#.*/([a-zA-Z0-9_-]+\.html)$#','$1','https://example.com.ua/part1/part2/part3/product-123.html');

you don't need a regex though to accomplish this task, and if you did it'd probably be cleaner to use preg_match.

Here's a preg_match approach:

preg_match('#[a-zA-Z0-9_-]+\.html$#', 'https://example.com.ua/part1/part2/part3/product-123.html', $match);
echo $match[0];

Demo: https://3v4l.org/4o9RM

Regex demo: https://regex101.com/r/6dytu0/2/

Angular Get last part of url

You can use ActivatedRoute interface, it contains the router state tree
within the angular app’s memory.

The parent property represents the parent of the route in the router state tree,
while the snapshot property is the current snapshot of the route and url is an
observable of the URL segments and it matched by this route.

Step 1: Import ActivatedRoute

    import { ActivatedRoute } from '@angular/router';

Step 2: Inject ActivatedRoute in constructor.

    constructor(private route: ActivatedRoute) { }

Step 3: Call it in Oninit lifecycle hook

      constructor(private route: ActivatedRoute){}
        
           ngOnInit() {
              this.route.parent.snapshot.url[2].path;
           }