Ruby: Array Contained in Array, Any Order

Check if two arrays have the same contents (in any order)

This doesn't require conversion to set:

a.sort == b.sort

Ruby: Array contained in Array, any order

def f a,b
    (a-b).empty?
end

How to determine if one array contains all elements of another array

a = [5, 1, 6, 14, 2, 8]
b = [2, 6, 15]

a - b
# => [5, 1, 14, 8]

b - a
# => [15]

(b - a).empty?
# => false

Array include every value from another array?

You can simply subtract one array from another, if the result is an empty array, all values are contained:

cheeses = %w[brie feta]
foods = %w[feta pizza brie bread]  
(cheeses - foods).empty?
#=>true

Array include any value from another array?

(cheeses & foods).empty?

As Marc-André Lafortune said in comments, & works in linear time while any? + include? will be quadratic. For larger sets of data, linear time will be faster. For small data sets, any? + include? may be faster as shown by Lee Jarvis' answer -- probably because & allocates a new Array while another solution does not and works as a simple nested loop to return a boolean.

Determining whether one array contains the contents of another array in ruby

You can use each_cons method:

arr = [1, 2, 3, 4, 5]
[1, 5, 8, 2, 3, 4, 5].each_cons(arr.size).include? arr

In this case it will work for any elements.

Order an array which contains OpenStructs by another array

Not clear whether you have numbers or strings as the attribute. If the former, then do

order.map!(&:to_i)

first. Then do:

a.sort_by!{|e| order.index(e.id)}

If there are no duplicates, do instead:

order & a.map(&:id)

Ruby - Does array A contain all elements of array B

This should work for what you need:

(a & b) == b

Sort an array of arrays based on the order in another array

h = x.to_h
# => {"ready"=>5,
# "shipped"=>1,
# "pending"=>1,
# "refunded"=>1,
# "delivered"=>23,
# "scheduled"=>1,
# "canceled"=>51}

order_array.map{|key| [key, h[key]] if h.key?(key)}.compact
# => [["ready", 5],
# ["shipped", 1],
# ["scheduled", 1],
# ["delivered", 23],
# ["canceled", 51],
# ["refunded", 1]]

or

h = x.to_h{|k, v| [k, [k, v]]}
#=> {"ready"=>["ready", 5],
# "shipped"=>["shipped", 1],
# "pending"=>["pending", 1],
# "refunded"=>["refunded", 1],
# "delivered"=>["delivered", 23],
# "scheduled"=>["scheduled", 1],
# "canceled"=>["canceled", 51]}

order_array.map{|k| h[k]}.compact
#=> [["ready", 5],
# ["shipped", 1],
# ["scheduled", 1],
# ["delivered", 23],
# ["canceled", 51],
# ["refunded", 1]]

or

h = x.to_h{|k, v| [k, [k, v]]}
#=> {"ready"=>["ready", 5],
# "shipped"=>["shipped", 1],
# "pending"=>["pending", 1],
# "refunded"=>["refunded", 1],
# "delivered"=>["delivered", 23],
# "scheduled"=>["scheduled", 1],
# "canceled"=>["canceled", 51]}

h.values_at(*order_array).compact
#=> [["ready", 5],
# ["shipped", 1],
# ["scheduled", 1],
# ["delivered", 23],
# ["canceled", 51],
# ["refunded", 1]]

Determine if one array contains all elements of another array

class Array
  def contains_all? other
    other = other.dup
    each{|e| if i = other.index(e) then other.delete_at(i) end}
    other.empty?
  end
end

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