Remove Portion of a String After a Certain Character

Remove portion of a string after a certain character

$variable = substr($variable, 0, strpos($variable, "By"));

In plain english: Give me the part of the string starting at the beginning and ending at the position where you first encounter the deliminator.

How to remove portion of string after certain character for each element of a Pandas series (or list)?

Using str.split

Ex:

s = pd.Series( ['AAA.B', 'BBB.C', 'CCC.D'])
print(s.str.split(".").str[0])

Output:

0    AAA
1    BBB
2    CCC
dtype: object

Remove portion of a string after a particular character from the end of the string

Use strrpos to get position of last matching element

//$variable = "8233 Station #2212"; //8233 Station
$variable = "8233 Station #2211 #2212";
echo trim(substr($variable, 0, strrpos($variable, "#"))); //8233 Station #2211

Remove text from string after a certain character in C

You can use strchr:

char str[] = "89f81a03eb30a03c8708dde38cf:000391716";
char *ptr;

ptr = strchr(str, ':');
if (ptr != NULL) {
    *ptr = '\0';
}

Remove everything after a certain character

You can also use the split() function. This seems to be the easiest one that comes to my mind :).

url.split('?')[0]

jsFiddle Demo

One advantage is this method will work even if there is no ? in the string - it will return the whole string.

Flutter - Remove String after certain character?

You can use the subString method from the String class

String s = "one.two";

//Removes everything after first '.'
String result = s.substring(0, s.indexOf('.'));
print(result);

In case there are more than one '.' in the String it will use the first occurrance. If you need to use the last one (to get rid of a file extension, for example) change indexOf to lastIndexOf. If you are unsure there is at least one occurrance, you should also add some validation to avoid triggering an exception.

String s = "one.two.three";

//Remove everything after last '.'
var pos = s.lastIndexOf('.');
String result = (pos != -1)? s.substring(0, pos): s;
print(result);

How to remove all characters after a specific character in python?

Split on your separator at most once, and take the first piece:

sep = '...'
stripped = text.split(sep, 1)[0]

You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case.

Remove characters after specific character in string, then remove substring?

For string manipulation, if you just want to kill everything after the ?, you can do this

string input = "http://www.somesite.com/somepage.aspx?whatever";
int index = input.IndexOf("?");
if (index >= 0)
   input = input.Substring(0, index);

Edit: If everything after the last slash, do something like

string input = "http://www.somesite.com/somepage.aspx?whatever";
int index = input.LastIndexOf("/");
if (index >= 0)
    input = input.Substring(0, index); // or index + 1 to keep slash

Alternately, since you're working with a URL, you can do something with it like this code

System.Uri uri = new Uri("http://www.somesite.com/what/test.aspx?hello=1");
string fixedUri = uri.AbsoluteUri.Replace(uri.Query, string.Empty);

How to remove all characters before a specific character in Java?

You can use .substring():

String s = "the text=text";
String s1 = s.substring(s.indexOf("=") + 1);
s1.trim();

then s1 contains everything after = in the original string.

s1.trim()

.trim() removes spaces before the first character (which isn't a whitespace, such as letters, numbers etc.) of a string (leading spaces) and also removes spaces after the last character (trailing spaces).

Delete all characters after a certain character from a string in Swift

You can use StringProtocol method range(of string:), get the resulting range lowerBound, create a PartialRangeUpTo with it and subscript the original string:

Swift 4 or later

let word = "orange"
if let index = word.range(of: "n")?.lowerBound {
    let substring = word[..<index]                 // "ora"
    // or  let substring = word.prefix(upTo: index) // "ora"
    // (see picture below) Using the prefix(upTo:) method is equivalent to using a partial half-open range as the collection’s subscript. 
    // The subscript notation is preferred over prefix(upTo:).

    let string = String(substring)
    print(string)  // "ora"
}

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