Get Img Src With PHP

Get img src with PHP

Use a HTML parser like DOMDocument and then evaluate the value you're looking for with DOMXpath:

$html = '<img id="12" border="0" src="/images/image.jpg"
         alt="Image" width="100" height="100" />';

$doc = new DOMDocument();
$doc->loadHTML($html);
$xpath = new DOMXPath($doc);
$src = $xpath->evaluate("string(//img/@src)"); # "/images/image.jpg"

Or for those who really need to save space:

$xpath = new DOMXPath(@DOMDocument::loadHTML($html));
$src = $xpath->evaluate("string(//img/@src)");

And for the one-liners out there:

$src = (string) reset(simplexml_import_dom(DOMDocument::loadHTML($html))->xpath("//img/@src"));

PHP get img src from xml

You have HTML embedded in XML tags, so you have to retrieve XML nodes, load each HTML and retrieve desired tag attribute.

In your XML there are different <description> nodes, so using ->getElementsByTagName will return more than your desired nodes. Use DOMXPath to retrieve only <description> nodes in the right tree position:

$dom = new DOMDocument();
libxml_use_internal_errors( True );
$dom->loadXML( $xml );
$dom->formatOutput = True;

$xpath = new DOMXPath( $dom );
$nodes = $xpath->query( 'channel/item/description' );

Then iterate all nodes, load node value in a new DOMDocument (no need to decode html entities, DOM already decodes it for you), and extract src attribute from <img> node:

foreach( $nodes as $node )
{
    $html = new DOMDocument();
    $html->loadHTML( $node->nodeValue );
    $src = $html->getElementsByTagName( 'img' )->item(0)->getAttribute('src');
}

eval.in demo

Assign Image SRC in php

Inside the HTML you still need to echo the value of $src. This should work:

<img id="img1" width="150" height="150" src="<?php echo $src; ?>"/>

PHP - How to get all urls from many img's src?

Use preg_match_all():

$src = <<<EOL
Its really great to <img src="image2.png" /> hear from you "Today is good
<img src="http://www.google.com/picture2.png" /> day" Let's listen song
together! ---------<img src="images/profile.png" />\\\\\\
EOL;

preg_match_all('~src="([^"]+)~', $src, $matches);

var_export($matches[1]);
// output ->
//        array (
//          0 => 'image2.png',
//          1 => 'http://www.google.com/picture2.png',
//          2 => 'images/profile.png',
//        )

Live demo

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Update: you can use \K in the regex pattern to get just what is needed in $matches:

preg_match_all('~src="\K[^"]+~', $src, $matches);
var_export($matches);
// output ->
//      array (
//        0 =>
//        array (
//          0 => 'image2.png',
//          1 => 'http://www.google.com/picture2.png',
//          2 => 'images/profile.png',
//        ),
//      )

For a reference see Escape sequences

Get img src with PHP Simple HTML DOM

You are having difficulty because javascipt is used to lazy load the image once the page is loaded. Use phpDom to find the Id of the element, and then use regular expression to find the relevant images based on this Id.

To achieve this, try something like :

$json = json_decode("<JSONSTRING HERE>");

foreach($html->find('div[class=profile_CF48B2B4A31B43EC96F0561F498CE6BF] a img') as $element) {
   $imgId = $element->getAttribute('id');

   foreach ($json as $lazy)
   {
      if ($lazy["id"] == $imgId) echo $lazy["data"];
   }
}

The above is untested so you will need to resolve the kinks. They key is to extract the relevant javascript and convert it to json.

Alternatively, you can use string search functions to get the row which contains the information about the img, and extract the required value.

PHP get image src

You can use an html parser for this. See this one: http://simplehtmldom.sourceforge.net/ (I hope this works for nodes, not just for entire pages).

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