Access JSON Object Name in PHP

Access JSON object name in PHP

I would imagine that the simplest thing to do is to decode into associative arrays instead of stdClass objects

$obj2 = json_decode( $json, true );

foreach ( $obj2['streets'] as $coords => $street )
{   
  echo $coords;
}

PHP get json object name

Use json_decode, list is also an array, Therefor first key(0) represent val0, and If you want to get inner content of the val0, then you have to loop it again.

$data = '{
  "STATUS": "SUCCESS",
  "MESSAGE": "",
  "DATA": {
    "list": [
      {
        "val0": {
          "hidden": "0",
          "rate": "10"
        }
      },
      {
        "val1": {
          "hidden": "0",
          "rate": "20"
        }
      }
    ],
    "cpe_status": "Provisioned"
  }
}';

$data = json_decode($data, true);

foreach($data['DATA']['list'][0] as $key=>$value){
    echo $key; // return val0
    echo "<br/>";
    // to get val0 inner content
    foreach($value as $item=>$list){
        echo $item." - ".$list; // return val0 inner data
        echo "<br/>";   
    }
}

// alternative way for loop val0 inner content
foreach($data['DATA']['list'][0]['val0'] as $key=>$value){
    echo $key." - ".$value; // return val0 inner data
    echo "<br/>";   
}

Using PHP to access JSON objects

You were nearly there - once you use json_decode, it's an object not an array, so you need to use '->' to access its contents like so - https://3v4l.org/ZZNDg

$properties = json_decode($json)->features[0]->properties;
echo($properties->name);

Access json object values with PHP

You already parse the Json in line 3.

You should be able to go $data[0]->userId or something

Edit: Notice that $data is an array of objects so you have to loop through them or specify which one of them you want to access. [] to choose an array element and then -> to access a field on the object

How to access JSON object without knowing its name (and that is not in an array)

You can access with the Object.keys to the name of the property in JavaScript.

var res = obj.body.measures[ obj.body.modules[0] ].res;
console.log( res[ Object.keys(res)[0] ][0]); // prints 7.9

See demo

EDIT (PHP version, only 2 lines):

With PHP is the same but using key and stdClass (json_decode returns stdClass)

$res = $obj->body->measures->{ $obj->body->modules[0] }->res;
echo $res->{ key( (array) $res ) }[0]; // prints 7.9

See demo

Hope help.

How to extract and access data from JSON with PHP?

Intro

First off you have a string. JSON is not an array, an object, or a data structure. JSON is a text-based serialization format - so a fancy string, but still just a string. Decode it in PHP by using json_decode().

 $data = json_decode($json);

Therein you might find:

• scalars: strings, ints, floats, and bools
• nulls (a special type of its own)
• compound types: objects and arrays.

These are the things that can be encoded in JSON. Or more accurately, these are PHP's versions of the things that can be encoded in JSON.

There's nothing special about them. They are not "JSON objects" or "JSON arrays." You've decoded the JSON - you now have basic everyday PHP types.

Objects will be instances of stdClass, a built-in class which is just a generic thing that's not important here.

---

Accessing object properties

You access the properties of one of these objects the same way you would for the public non-static properties of any other object, e.g. $object->property.

$json = '
{
    "type": "donut",
    "name": "Cake"
}';

$yummy = json_decode($json);

echo $yummy->type; //donut

---

Accessing array elements

You access the elements of one of these arrays the same way you would for any other array, e.g. $array[0].

$json = '
[
    "Glazed",
    "Chocolate with Sprinkles",
    "Maple"
]';

$toppings = json_decode($json);

echo $toppings[1]; //Chocolate with Sprinkles

Iterate over it with foreach.

foreach ($toppings as $topping) {
    echo $topping, "\n";
}

Glazed

Chocolate with Sprinkles

Maple

Or mess about with any of the bazillion built-in array functions.

---

Accessing nested items

The properties of objects and the elements of arrays might be more objects and/or arrays - you can simply continue to access their properties and members as usual, e.g. $object->array[0]->etc.

$json = '
{
    "type": "donut",
    "name": "Cake",
    "toppings": [
        { "id": "5002", "type": "Glazed" },
        { "id": "5006", "type": "Chocolate with Sprinkles" },
        { "id": "5004", "type": "Maple" }
    ]
}';

$yummy = json_decode($json);

echo $yummy->toppings[2]->id; //5004

---

Passing true as the second argument to json_decode()

When you do this, instead of objects you'll get associative arrays - arrays with strings for keys. Again you access the elements thereof as usual, e.g. $array['key'].

$json = '
{
    "type": "donut",
    "name": "Cake",
    "toppings": [
        { "id": "5002", "type": "Glazed" },
        { "id": "5006", "type": "Chocolate with Sprinkles" },
        { "id": "5004", "type": "Maple" }
    ]
}';

$yummy = json_decode($json, true);

echo $yummy['toppings'][2]['type']; //Maple

---

Accessing associative array items

When decoding a JSON object to an associative PHP array, you can iterate both keys and values using the foreach (array_expression as $key => $value) syntax, eg

$json = '
{
    "foo": "foo value",
    "bar": "bar value",
    "baz": "baz value"
}';

$assoc = json_decode($json, true);
foreach ($assoc as $key => $value) {
    echo "The value of key '$key' is '$value'", PHP_EOL;
}

Prints

The value of key 'foo' is 'foo value'

The value of key 'bar' is 'bar value'

The value of key 'baz' is 'baz value'

---

Don't know how the data is structured

Read the documentation for whatever it is you're getting the JSON from.

Look at the JSON - where you see curly brackets {} expect an object, where you see square brackets [] expect an array.

Hit the decoded data with a print_r():

$json = '
{
    "type": "donut",
    "name": "Cake",
    "toppings": [
        { "id": "5002", "type": "Glazed" },
        { "id": "5006", "type": "Chocolate with Sprinkles" },
        { "id": "5004", "type": "Maple" }
    ]
}';

$yummy = json_decode($json);

print_r($yummy);

and check the output:

stdClass Object
(
    [type] => donut
    [name] => Cake
    [toppings] => Array
        (
            [0] => stdClass Object
                (
                    [id] => 5002
                    [type] => Glazed
                )

            [1] => stdClass Object
                (
                    [id] => 5006
                    [type] => Chocolate with Sprinkles
                )

            [2] => stdClass Object
                (
                    [id] => 5004
                    [type] => Maple
                )

        )

)

It'll tell you where you have objects, where you have arrays, along with the names and values of their members.

If you can only get so far into it before you get lost - go that far and hit that with print_r():

print_r($yummy->toppings[0]);

stdClass Object
(
    [id] => 5002
    [type] => Glazed
)

Take a look at it in this handy interactive JSON explorer.

Break the problem down into pieces that are easier to wrap your head around.

---

json_decode() returns null

This happens because either:

1. The JSON consists entirely of just that, null.
2. The JSON is invalid - check the result of json_last_error_msg or put it through something like JSONLint.
3. It contains elements nested more than 512 levels deep. This default max depth can be overridden by passing an integer as the third argument to json_decode().

If you need to change the max depth you're probably solving the wrong problem. Find out why you're getting such deeply nested data (e.g. the service you're querying that's generating the JSON has a bug) and get that to not happen.

---

Object property name contains a special character

Sometimes you'll have an object property name that contains something like a hyphen - or at sign @ which can't be used in a literal identifier. Instead you can use a string literal within curly braces to address it.

$json = '{"@attributes":{"answer":42}}';
$thing = json_decode($json);

echo $thing->{'@attributes'}->answer; //42

If you have an integer as property see: How to access object properties with names like integers? as reference.

---

Someone put JSON in your JSON

It's ridiculous but it happens - there's JSON encoded as a string within your JSON. Decode, access the string as usual, decode that, and eventually get to what you need.

$json = '
{
    "type": "donut",
    "name": "Cake",
    "toppings": "[{ \"type\": \"Glazed\" }, { \"type\": \"Maple\" }]"
}';

$yummy = json_decode($json);
$toppings = json_decode($yummy->toppings);

echo $toppings[0]->type; //Glazed

---

Data doesn't fit in memory

If your JSON is too large for json_decode() to handle at once things start to get tricky. See:

• Processing large JSON files in PHP
• How to properly iterate through a big json file

---

How to sort it

See: Reference: all basic ways to sort arrays and data in PHP.

How to access object in php when the identifier starts with a @ symbol?

Keep element name in one variable like $test and use $var->$test to get value like this

 <?php
    $arr = json_decode(json_encode(["@id"=> "1EBEF5DA"]));
    $obj = '@id';
    print_r($arr->$obj);
 ?>

Demo : https://eval.in/844662

Or another way is print_r($arr->{'@id'});

Demo : https://eval.in/844662

Accessing JSON object elements in PHP

If you are using json_decode($json,true); - true means returning the js objects results as associative arrays - then all you have to do is $user_info = $jsonDecoded['USER']; without the array() cast cause that is what json_decode do for you.

If you would choose to omit the second boolean parameter then you will get an stdClass which $jsonDecoded->USER; would work for you

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