Choose File Dialog

Choose File Dialog

You just need to override onCreateDialog in an Activity.

//In an Activity
private String[] mFileList;
private File mPath = new File(Environment.getExternalStorageDirectory() + "//yourdir//");
private String mChosenFile;
private static final String FTYPE = ".txt";    
private static final int DIALOG_LOAD_FILE = 1000;

private void loadFileList() {
    try {
        mPath.mkdirs();
    }
    catch(SecurityException e) {
        Log.e(TAG, "unable to write on the sd card " + e.toString());
    }
    if(mPath.exists()) {
        FilenameFilter filter = new FilenameFilter() {

            @Override
            public boolean accept(File dir, String filename) {
                File sel = new File(dir, filename);
                return filename.contains(FTYPE) || sel.isDirectory();
            }

        };
        mFileList = mPath.list(filter);
    }
    else {
        mFileList= new String[0];
    }
}

protected Dialog onCreateDialog(int id) {
    Dialog dialog = null;
    AlertDialog.Builder builder = new Builder(this);

    switch(id) {
        case DIALOG_LOAD_FILE:
            builder.setTitle("Choose your file");
            if(mFileList == null) {
                Log.e(TAG, "Showing file picker before loading the file list");
                dialog = builder.create();
                return dialog;
            }
            builder.setItems(mFileList, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int which) {
                    mChosenFile = mFileList[which];
                    //you can do stuff with the file here too
                }
            });
            break;
    }
    dialog = builder.show();
    return dialog;
}

How to open select file dialog via js?

Using jQuery

I would create a button and an invisible input like so:

<button id="button">Open</button>
<input id="file-input" type="file" name="name" style="display: none;" />

and add some jQuery to trigger it:

$('#button').on('click', function() {
    $('#file-input').trigger('click');
});

Using Vanilla JS

Same idea, without jQuery (credits to @Pascale):

<button onclick="document.getElementById('file-input').click();">Open</button>
<input id="file-input" type="file" name="name" style="display: none;" />

Quick and easy file dialog in Python?

Tkinter is the easiest way if you don't want to have any other dependencies.
To show only the dialog without any other GUI elements, you have to hide the root window using the withdraw method:

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()
root.withdraw()

file_path = filedialog.askopenfilename()

Python 2 variant:

import Tkinter, tkFileDialog

root = Tkinter.Tk()
root.withdraw()

file_path = tkFileDialog.askopenfilename()

How to choose file in java?

Here is the example from the JFileChooser docs copy pasta with the parent sent to null.

public class PickAFile {
    public static void main(String[] args){
        JFileChooser chooser = new JFileChooser();
        FileNameExtensionFilter filter = new FileNameExtensionFilter(
                "JPG & GIF Images", "jpg", "gif");
        chooser.setFileFilter(filter);
        int returnVal = chooser.showOpenDialog(null);
        if(returnVal == JFileChooser.APPROVE_OPTION) {
            System.out.println("You chose to open this file: " +
                    chooser.getSelectedFile().getName());
        }
    }
}

If you don't like the look of the JFileChooser try the FileDialog.

    FileDialog dialog = new FileDialog((Frame)null, "Select File to Open");
    dialog.setMode(FileDialog.LOAD);
    dialog.setVisible(true);
    String file = dialog.getFile();
    System.out.println(file + " chosen.");

Choose file dialog errors

It seems you decided to use char array to receive the path and GetOpenFileNameA() function, so OPENFILENAMEA structure should be used.

OPENFILENAME ofn;
ZeroMemory(&filename, sizeof(filename));
ZeroMemory(&ofn, sizeof(ofn));
ofn.lStructSize = sizeof(ofn);
ofn.hwndOwner = NULL;  
ofn.lpstrFilter = L"Text Files\0*.txt\0Any File\0*.*\0";
ofn.lpstrFile = filename;
ofn.nMaxFile = MAX_PATH;
ofn.lpstrTitle = L"Select a File, yo!";
ofn.Flags = OFN_DONTADDTORECENT | OFN_FILEMUSTEXIST;

should be

OPENFILENAMEA ofn;
ZeroMemory(&filename, sizeof(filename));
ZeroMemory(&ofn, sizeof(ofn));
ofn.lStructSize = sizeof(ofn);
ofn.hwndOwner = NULL;  
ofn.lpstrFilter = "Text Files\0*.txt\0Any File\0*.*\0";
ofn.lpstrFile = filename;
ofn.nMaxFile = MAX_PATH;
ofn.lpstrTitle = "Select a File, yo!";
ofn.Flags = OFN_DONTADDTORECENT | OFN_FILEMUSTEXIST;

(add A to the structure name and remove L prefix from the strings)

Open choose file dialog box on onclick of Raised Button Material ui

Basic example (does not include what to do with selected file):

  <div>
    <input id="myInput" type="file" ref={(ref) => this.upload = ref} style={{ display: 'none' }} />
    <FloatingActionButton
      className="floatingButton"
      backgroundColor='#293C8E'
      onClick={(e) => this.upload.click() }
      >
      <ContentAdd />
    </FloatingActionButton>
  </div>

So, your FloatingActionButton's onClick handler manually fires the click() handler of a hidden file upload control (input type="file"). A reference to the hidden upload control is obtained by putting a ref callback on it and storing that reference in "this.upload" (could also use DOM or jQuery to do that, but ref is preferred in React)

here is a working jsFiddle: https://jsfiddle.net/432yz8qg/58/

click on input box to show open file dialog but not click on choose file button

You can overlay a transparent <input type="file"/> over a styled button or other element.

<input type="file" style="opacity:0;"/>

See this JSFiddle for a working demo.

Choosing a file in Python with simple Dialog

How about using tkinter?

from Tkinter import Tk     # from tkinter import Tk for Python 3.x
from tkinter.filedialog import askopenfilename

Tk().withdraw() # we don't want a full GUI, so keep the root window from appearing
filename = askopenfilename() # show an "Open" dialog box and return the path to the selected file
print(filename)

Done!

c++ win32 console app adding a choose file dialog box using windows api

The method Microsoft normally advocates is to use their "generic text" macros, so your string literals would look like this:

ofn.lpstrFilter = _T("Text Files\0*.txt\0Any File\0*.*\0");
ofn.lpstrTitle = _T("Select a File, yo!");

This way, you can build for narrow or wide character strings (the latter by defining UNICODE and _UNICODE). The _T will map to nothing for a narrow-character build, and to a L for a wide-character build, so you automatically get the right kind of string for the way you're building.

To use this, you include <tchar.h>.

For example:

#include <iostream>
#include <tchar.h>

#ifndef NOMINMAX
#define NOMINMAX
#endif
#include <windows.h>

int main()
{
  char filename[ MAX_PATH ];

  OPENFILENAME ofn;
    ZeroMemory( &filename, sizeof( filename ) );
    ZeroMemory( &ofn,      sizeof( ofn ) );
    ofn.lStructSize  = sizeof( ofn );
    ofn.hwndOwner    = NULL;  // If you have a window to center over, put its HANDLE here
    ofn.lpstrFilter  = _T("Text Files\0*.txt\0Any File\0*.*\0");
    ofn.lpstrFile    = filename;
    ofn.nMaxFile     = MAX_PATH;
    ofn.lpstrTitle   = _T("Select a File, yo!");
    ofn.Flags        = OFN_DONTADDTORECENT | OFN_FILEMUSTEXIST;

  if (GetOpenFileName( &ofn ))
  {
    std::cout << "You chose the file \"" << filename << "\"\n";
  }
  else
  {
    // All this stuff below is to tell you exactly how you messed up above. 
    // Once you've got that fixed, you can often (not always!) reduce it to a 'user cancelled' assumption.
    switch (CommDlgExtendedError())
    {
      case CDERR_DIALOGFAILURE   : std::cout << "CDERR_DIALOGFAILURE\n";   break;
      case CDERR_FINDRESFAILURE  : std::cout << "CDERR_FINDRESFAILURE\n";  break;
      case CDERR_INITIALIZATION  : std::cout << "CDERR_INITIALIZATION\n";  break;
      case CDERR_LOADRESFAILURE  : std::cout << "CDERR_LOADRESFAILURE\n";  break;
      case CDERR_LOADSTRFAILURE  : std::cout << "CDERR_LOADSTRFAILURE\n";  break;
      case CDERR_LOCKRESFAILURE  : std::cout << "CDERR_LOCKRESFAILURE\n";  break;
      case CDERR_MEMALLOCFAILURE : std::cout << "CDERR_MEMALLOCFAILURE\n"; break;
      case CDERR_MEMLOCKFAILURE  : std::cout << "CDERR_MEMLOCKFAILURE\n";  break;
      case CDERR_NOHINSTANCE     : std::cout << "CDERR_NOHINSTANCE\n";     break;
      case CDERR_NOHOOK          : std::cout << "CDERR_NOHOOK\n";          break;
      case CDERR_NOTEMPLATE      : std::cout << "CDERR_NOTEMPLATE\n";      break;
      case CDERR_STRUCTSIZE      : std::cout << "CDERR_STRUCTSIZE\n";      break;
      case FNERR_BUFFERTOOSMALL  : std::cout << "FNERR_BUFFERTOOSMALL\n";  break;
      case FNERR_INVALIDFILENAME : std::cout << "FNERR_INVALIDFILENAME\n"; break;
      case FNERR_SUBCLASSFAILURE : std::cout << "FNERR_SUBCLASSFAILURE\n"; break;
      default                    : std::cout << "You cancelled.\n";
    }
  }
}

To get a "save" filename instead, just change the GetOpenFilename to GetSaveFilename. There are a few differences in the flags you're likely to pass in the OPENFILENAME though--for example, it's pretty common to pass OFN_FILEMUSTEXIST when you're opening a file, but you almost never want to when you're saving a file.

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