How to Display an Int Without Commas

Python : How to format large number without comma

you may use:

print "number : {0:.0f}".format(b)

the zero after dot determines how many decimal digits you want after the the decimal mark. :)

extra:

you don't have to combine strings, just write them as one. It is easier to understand later.

You can check the index before printing

n = int(input("Enter a number :-"))
for i in range(1, 11):
    end = "," if i < 10 else ""
    print(i*n, end = end)

There is no such format :-(

As kind of a hack, you could apply a conditional formatting.

As base numberformat use 0,00;-0,00;""

Plus apply the following conditional formatting:

You can do this :

>>> string = '82,000,00'
>>> int(price_result.replace(',', ''))
8200000

See the documentation for number_format: http://php.net/number_format

The functions parameters are:

string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )

So use:

number_format(1000.5, 2, '.', '');

Which means that you don't use any (= empty string) thousands separator, only a decimal point.

int[] arr = new int[]{2, 3, 4, 1, 5};
String res = Arrays.toString(arr).replaceAll("[\\[\\],]", "");
System.out.println(res);

You may merge these 2 patterns of yours like

^[+-]?[0-9]+(?:,[0-9]+)*(?:[.][0-9]+)?$

See the regex demo

Details:

^ - start of a string
[+-]? - an optional + or -
[0-9]+ - 1 or more digits
(?:,[0-9]+)* - zero or more sequences of:
- , - a comma
- [0-9]+ - 1 or more digits
(?:[.][0-9]+)? - an optional sequence of:
- [.] - a dot
- [0-9]+ - 1+ digits
$ - end of string

A more restrictive regex to only allow 3-digits in groupings will look like

^[+-]?[0-9]{1,3}(?:,[0-9]{3})*(?:[.][0-9]+)?$
           ^^^^^         ^^^

And if you want to also match whole parts with no thousand separators:

^[+-]?(?:[0-9]{1,3}(?:,[0-9]{3})*|[0-9]+)(?:[.][0-9]+)?$