How to Tell Python to Convert Integers into Words

How to convert an integer number to words in python?

Use modules for it:
https://pypi.python.org/pypi/num2words

Also, check similar questions: How do I tell Python to convert integers into words

You can install the modules and see how it is implemented there.

But your problem is solved like:

def numbers_to_words (number):
    number2word = {'1': "one", '2': "two", '3': "three", '4': "four", '5': "five", '6': "six",
            '7': "seven", '8': "eight", '9': "nine", '0': "zero"}
    return " ".join(map(lambda i: number2word[i], str(number)))


print(numbers_to_words(1234))

How to convert numbers to words without using num2word library?

Your first statement logic is incorrect. Unless Number is 1 or smaller, that statement is always True; 200 is greater than 1 as well.

Use and instead, and include 1 in the acceptable values:

if (Number >= 1) and (Number <= 19):

You could use chaining as well:

if 1 <= Number <= 19:

For numbers of 20 or larger, use divmod() to get both the number of tens and the remainder:

tens, remainder = divmod(Number, 10)

Demo:

>>> divmod(42, 10)
(4, 2)

then use those values to build your number from the parts:

return num2words2[tens - 2] + '-' + num2words1[below_ten]

Don't forget to account for cases when the number is above 20 and doesn't have a remainder from the divmod operation:

return num2words2[tens - 2] + '-' + num2words1[remainder] if remainder else num2words2[tens - 2]

All put together:

def number(Number):
    if 0 <= Number <= 19:
        return num2words1[Number]
    elif 20 <= Number <= 99:
        tens, remainder = divmod(Number, 10)
        return num2words2[tens - 2] + '-' + num2words1[remainder] if remainder else num2words2[tens - 2]
    else:
        print('Number out of implemented range of numbers.')

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