Django - Button Url

Reference Django URL in HTML Button

Your specific problem is that you have a conflict with quote types. Use this instead:

onclick="location.href='{% url 'customeroverview' %}'"

but note that this is not really a good way of doing things. If you just want a link that looks like a button, then have a normal a href and use CSS to style it like a button. In Bootstrap, for example, you can use the "btn btn-*" classes on any element to make it look like a button.

Django - button url

Note: path(..) is available from Django-2.0.

The problem here is that friend is not in the URL:

url(r'^add_friend/$', views.friend_add, name="add_friend"),  # no parameter

You can for instance use the primary key (pk) for the friend by specifying a path(..):

path(r'add_friend/<int:friend>/', views.friend_add, name="add_friend"),

In case you work with django-1.x, you can use url(..) with a regex:

url(r'^add_friend/(?P<friend>[0-9]+)/$', views.friend_add, name="add_friend"),

And now we can use the primary key of the friend in the reverse url:

<input
    type="button"
    class="btn btn-info"
    value="Add Friend"
    onclick="location.href='{% url 'user:add_friend' friend=post.poster.pk %}';"
>

(multi-line to make it easier to read).

Attach link to a button in Django

This is HTML problem which you can solve in many ways. One such way is below.

<form>
    <button formaction="{% url 'javascript:results' %}">Selenium</button>
</form>

How to use a button to point to an existing url

You can make use of the {% url … %} template tag [Django-doc]:

<li>
    <a href="{% url 'detail' question_id=question.pk">
        {{ question.question_text }}</a></li>
        <button type='submit'> Result
        </button>
    </a>
</li>

How can I create redirect button with post method in Django template

from django.conf.urls import include, url
from django.contrib import admin
from rtRegRes.views import spartan , units

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^units/$', units),
    url(r'^units/sts/?$', spartan, name='sts'),
]

and

<form method="post" action='sts'>
{% csrf_token %}
 <button class="btn btn-outline-success my-2 my-sm-0" type="submit" name="cts_link">cts</button>
</form>

DJango - Redirect to another apps / from a button click

You can use Django URL tag.

<a href="{% url 'myapp:view-name' %}">My link</a>

Example :

<a href="{% url 'portfolio:view-name' %}">Portfolio</a>

Django - How to pass current url parameters if any to a new url after pressing a button

EDIT since the question changed:
It makes more sense to do a POST here probably instead of a GET.

path('export_wallet/', views.export_wallet_view, name='export_wallet'), 

.inline {
  display: inline;
}

.link-button {
  background: none;
  border: none;
  color: blue;
  text-decoration: underline;
  cursor: pointer;
  font-size: 1em;
  font-family: serif;
}
.link-button:focus {
  outline: none;
}
.link-button:active {
  color:red;
}

<form method="post" action="{% url 'export_wallet' %}" class="inline">
  <input type="hidden" name="fecha_inicio" value="{{ fecha_inicio }}">
<input type="hidden" name="fecha_fin" value="{{ fecha_fin }}">
  <button type="submit" name="submit_param" value="submit_value" class="link-button">
    This is a link that sends a POST request
  </button>
</form>

var auxBack = performance.getEntriesByType("navigation");

if (auxBack[0].type === "back_forward") {
    location.reload(true);
}