Python: How to Keep Repeating a Program Until a Specific Input Is Obtained

Python: How to keep repeating a program until a specific input is obtained?

There are two ways to do this. First is like this:

while True:             # Loop continuously
    inp = raw_input()   # Get the input
    if inp == "":       # If it is a blank line...
        break           # ...break the loop

The second is like this:

inp = raw_input()       # Get the input
while inp != "":        # Loop until it is a blank line
    inp = raw_input()   # Get the input again

Note that if you are on Python 3.x, you will need to replace raw_input with input.

How to repeat a section of the program until the input is correct?

Add a while-loop there. This means you're looping the question again infinitely until you've reached a satisfactory result.

while True:
    ghuess=input("state a number between 1-100")
    if ghuess>number:
        print "too high try again!"
    elif ghuess<number:
        print "too low try again!"
    else:
        # Jackpot, exit the loop.
        break
print "well done! ghuess you have won.."
time.sleep(1)
print "3"
time.sleep(1)
print "2"
time.sleep(1)
print "1"
time.sleep(1)
print prize

How do I make a program keep repeating until I input a specific data that stops it?

Here it is:

def program():
    pass


user_input = int(input())

while user_input:
    program()
    user_input = int(input())

quit(0)

How to keep repeating a program until a specific input?

Just move the input into the loop:

x = None
lis = []
while x != '':
    x = input('Enter a number: ')
    if x != '':
        lis.append(int(x))
avg = sum(lis) / len(lis)
print(avg)

Also you don't need the if statement as x must be equal to '' anyway so that the while loop terminates.

How to use a While Loop to repeat the code based on the input variable

Firstly you should remove

value = input("number?:\n")
print(f'you have chosen: {value}')
value = int(value)

from the top of your code, everything must be inside your __main__ program.

Basically what you need to do is create a main While loop where your program is gonna run, it will keeps looping until the response is not "yes".

For each iteration, you ask a new number at the beggining and if it has to keep looping at the end.

Something like this:

# driver program
if __name__ == '__main__':
    # starts as "yes" for first iteration
    pitanje = "yes"

    while pitanje == "yes":
        # asks number
        value = input("number?:\n")
        print(f'you have chosen: {value}')
        value = int(value)

        # show results
        start: SieveOfEratosthenes(value)

        # asks for restart
        pitanje = input("do you want to continue(yes/no)?")

    #if it's in here the response wasn't "yes"
    print("goodbye")

How to repeat the input until a special condition is meet in Python?

When the exception happens, a remains unset. Try this instead.

s = set()
# Notice also correct quoting
print("Please type the number, when you're done please type 'Done':")
while True:
    a = input()
    try:
        n = int(a)
        s.add(n)
    # Avoid blanket except
    except ValueError:
        if a == "Done":
            break
        else:
            print('Integer only, please re-type:')
            continue
print(s)

Loop until a specific user input

As an alternative to @Mark Byers' approach, you can use while True:

guess = 50     # this should be outside the loop, I think
while True:    # infinite loop
    n = raw_input("\n\nTrue, False or Correct?: ")
    if n == "Correct":
        break  # stops the loop
    elif n == "True":
        # etc.

Loop from the start of the code until the user says stop in Python

I solve your problem by moving your inner while loop into the else case. Also, in the if statement N == 'Y', I insert one more N = input(...) command:

N = input("Do you want to continue to find factors Y/N: ").upper()
while True:
    if N == 'Y':
        print_factors(int(input("Enter a number: ")))
        N = input("Do you want to continue to find factors Y/N: ").upper()
        
    elif N == 'N':
        break
    else:
        while N not in 'YN':
            print("Invalid input, please try again.")
            N = input("Do you want to continue to find factors Y/N: ").upper()

Result:

Please enter a number: 15
The factors of 15 are: 
1
3
5
15
Do you want to continue to find factors Y/N: y
Enter a number: 23
The factors of 23 are: 
1
23
Do you want to continue to find factors Y/N: e
Invalid input, please try again.
Do you want to continue to find factors Y/N: y
Enter a number: 32
The factors of 32 are: 
1
2
4
8
16
32
Do you want to continue to find factors Y/N: n
>>>

• Side note: running on Python 3.9.1, Window 10.
• Maybe you would want to include the same try-catch block into the user-controlled while loop.

---

Related Topics