How to remove additional commas in a list in python
x = ['apples', ',', 'orange', ',', 'grapes']
x = list(filter(lambda v: v != ',', x))
print(x)
another alternative:
x = [v for v in x if v != ',']
results in:
['apples', 'orange', 'grapes']
How to remove the extra commas from the list of email addresses
No need for regular expressions. Use .split(',')
to split into a list of strings.
email_lst = email_addr.split(',')
Then join with comma, but filter out blank values
email_addr2 = ",".join(e.strip() for e in email_lst if e.strip())
# 'test@domain.com,test1@domain.com,test2@domain.com'
In Python 3.8+, you can use the walrus operator to avoid calling .strip()
twice:
email_addr2 = ",".join(e for ee in email_lst if (e := ee.strip()))
Removing all commas from list in Python
I would use the following:
# Get an array of numbers
numbers = map(float, '1,2,3,4'.split(','))
# Now get the sum
total = sum(numbers)
Is there a way to remove all comma's in a list?
You could use a list comprehension, and extract integers from the strings using string.replace
to remove all the ','
:
l = ['10', '1,000', '51,000', '500', '63,000']
[int(s.replace(',','')) for s in l]
# [10, 1000, 51000, 500, 63000]
how to remove a comma from a list
Also you can use: str(my_list1).replace( ',' , ' ' )
Python how to remove unwanted commas in a dataframe containing lists as element
df['data'] = df.data.replace(to_replace=r',,', value='', regex=True)
print(df)
get rid of commas in a list python
If you want a numpy ndarray, use:
np.array([1, 2, 4, 7, 5, 2])
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