How to Extract Integer or Float from String

How to extract a floating number from a string

If your float is always expressed in decimal notation something like

>>> import re
>>> re.findall("\d+\.\d+", "Current Level: 13.4db.")
['13.4']

may suffice.

A more robust version would be:

>>> re.findall(r"[-+]?(?:\d*\.\d+|\d+)", "Current Level: -13.2db or 14.2 or 3")
['-13.2', '14.2', '3']

If you want to validate user input, you could alternatively also check for a float by stepping to it directly:

user_input = "Current Level: 1e100 db"
for token in user_input.split():
    try:
        # if this succeeds, you have your (first) float
        print float(token), "is a float"
    except ValueError:
        print token, "is something else"

# => Would print ...
#
# Current is something else
# Level: is something else
# 1e+100 is a float
# db is something else
        

Extract int digits and float number from a python string

How about regular expressions?

Example

>>> import re
>>> str1="107.8X98x3.75"
>>> re.findall(r'\d+(?:\.\d+)?', str1)
['107.8', '98', '3.75']

Extract Float Value or Integer Value from string

Simply remove the commas before matching:

str.delete(',').match(/\d+\.\d+/)[0]

How can I extract a floating point number from a string efficiently?

Use this:

        float number = Float.parseFloat(s.replaceAll("[^\\d.]", ""));
        System.out.println(number);

Or, what's already mentioned in the comments:
Get the substring which only contains the number. Then you can parse it to your data type.

        String s = "0.0234000ETH";
        String part1 = s.substring(0,8);
        float value = Float.parseFloat(part1);
        System.out.println(value);

Regex to extract both integer or float values followed by a unit, Python

You can try with this:

([.\d]+)\s*(?:mg|kg|ml|q.s.|ui|M|g|µg)

Try it online.

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