I Need to Code a 1 22 333 4444 Pattern in Python With While Loops

I need to code a 1 22 333 4444 pattern in python with while loops

This is the idiomatic way to do it in Python, using the fact that a string can be "multiplied":

def EXwhile6 ():
    a = input("Write how many lines you want to print: ")
    a = int(a)
    K = 1
    while K <= a:
        print(str(K) * K)
        K += 1

Now, if you want to code it by hand you'd need a nested loop; the above is equivalent to:

def EXwhile6 ():
    a = input("Write how many lines you want to print: ")
    a = int(a)
    K = 1
    while K <= a:
        J = 1
        while J <= K:
            print(K, end="")
            J += 1
        print()
        K += 1

Python | addition of pattern 1 22 333 4444 55555​ ....?

You generate a sequence of elements of the form str(i)*i, which you cast into an integer, then sum that sequence.

def create_sequence(n):
    return sum(int(str(i)*i) for i in range(1, n+1))

create_sequence(int(input('Enter the number till which you want the sequence: ')))

How to create the pattern like 55555,4444,333,22,1 using loop structures in R

You can do :

n <- 5
for(x in n:1){
  cat(rep(x, x), '\n')
}

#5 5 5 5 5 
#4 4 4 4 
#3 3 3 
#2 2 
#1 

Another version without a loop :

n1 <- n:1
cat(paste0(strrep(n1, n1), collapse = '\n'))

How to print numbers in the following pattern with .NET

The problem is in the MakeALine method. You actually concat the number with itself, so for input 1 you actually get "1" + "1".

Instead you should repeat the string representation of your number k times. For this you can use Enumerable.Repeat in the following way:

static string MakeALine(int k)
{
    return String.Concat(Enumerable.Repeat(k.ToString(),k));
}

Creating number pattern with minimum for loops

here you are:

for (int i = 1, j = 1 ; i < 10 ; i++, j = (i <= 5) ? (j*10 + 1) : (j/10))
    System.out.println(i * j); 

How to make this numbers triangle using nested while loops? (python 2.7)

Do you require nested loops?

>>> n=5
>>> for i in range(1, n+1):
...     print("{:>{width}}".format(str(i)*i, width=n))
    1
   22
  333
 4444
55555

But to fix your code - you are missing the multiplier on your number:

n=5
m=1
while n>=1:
    while m<=5:
        print " "*(n), str(m)*m
        n=n-1
        m=m+1

how to generate pattern 5 5 5 5 5 4 4 4 4 3 3 3 2 2 1

Beginners should help beginners :-)

Here a slightly different approach:

for (int i=0; i <= 5; i++)
{
    for (int j=0; j<5 ; j++)
    {
        if (j >= i)
            printf("%1d ", 5-i);
        else
            printf("  ");
    }
    printf("\n");
}

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