Convert Timedelta to Floating-Point

Convert timedelta to floating-point

You could use the total_seconds method:

time_d_float = time_d.total_seconds()

Convert timedelta to floating-point for entire column in data frame

Use Series.dt.days for processing Series:

df['column'] = df['column'].dt.days

timedelta to float python

You just need to convert the Days column to integer format and plot as normal:

df['daysInt'] = df['Days'].apply(lambda x: x.days)

...will give you the int column, and you know the rest.

How to convert float to timedelta seconds in python?

Just use

value = timedelta(seconds=43880.6543)

You can check the value is ok with

value.total_seconds()

Edit: If, in an Excel spreadsheet, you have a date expressed as a number, you can use python to convert that number into a datetime by doing this:

value = datetime(1900, 1, 1) + timedelta(days=43880.6543)
# value will be February 2nd, 2020 in the afternoon

Python: Pandas Dataframe How to Convert timedelta column to float column

You can use apply and lambda to access the attribute days (https://pandas.pydata.org/pandas-docs/stable/timedeltas.html):

df_EVENT5_24['ColA'] = df_EVENT5_24.apply(lambda row: row.ColA.days, axis=1)

python datetime to float with millisecond precision

Python 2:

def datetime_to_float(d):
    epoch = datetime.datetime.utcfromtimestamp(0)
    total_seconds =  (d - epoch).total_seconds()
    # total_seconds will be in decimals (millisecond precision)
    return total_seconds

def float_to_datetime(fl):
    return datetime.datetime.fromtimestamp(fl)

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Python 3:

def datetime_to_float(d):
    return d.timestamp()

The python 3 version of float_to_datetime will be no different from the python 2 version above.

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