PHP Shorthand for Isset()

PHP shorthand for isset()?

Update for PHP 7 (thanks shock_gone_wild)

PHP 7 introduces the null coalescing operator which simplifies the below statements to:

$var = $var ?? "default";

Before PHP 7

No, there is no special operator or special syntax for this. However, you could use the ternary operator:

$var = isset($var) ? $var : "default";

Or like this:

isset($var) ?: $var = 'default';

Shorthand isset(), if not, return default value

https://stackoverflow.com/a/18603279/165330 :

before php 7 : no

$address = isset($node->field_naam_adres['und'][0]['value']) ? $node->field_naam_adres['und'][0]['value'] : '';

from php 7 : yes

$address = $node->field_naam_adres['und'][0]['value'] ?? 'default';

Shorthand for isset and !empty

isset and empty are both language constructs. And empty() internally does an isset check first, then negates that, or alternatively also checks for values that equate FALSE in boolean context.

So yes, !empty() is sufficient.

Get value of variable when isset() is used in PHP ternary shorthand operator

It sounds like you are asking about the new (as of PHP 7) null coalesce operator. You can do something like:

$foo = $_GET['bar'] ?? 'hello';
echo $foo;

Which if $_GET['bar'] is null will set $foo to hello.

The first operand from left to right that exists and is not NULL. NULL if no values are defined and not NULL. Available as of PHP 7.

Functional demo: https://3v4l.org/0CfbE

$foo = $_GET['bar'] ?? 'hello';
echo $foo . "\n";
$_GET['bar'] = 'good bye';
$foo = $_GET['bar'] ?? 'hello';
echo $foo;

Output:

hello
good bye

Additional reading on it: http://www.lornajane.net/posts/2015/new-in-php-7-null-coalesce-operator

PHP shorthand for if (!isset($var)) $var = 1;

Yes it's called the ternary operator:

$var = isset($var) ? $var : "Some default";

Since PHP 5.3 there's a shorthand version for this as well:

$var = isset($var) ?: "Some default";

And an alternate version for PHP 5.3+:

isset($var) ?: $var = "Some default";

Shorthand check if variable isset or not and echo them to value of input field

You need to use brackets round your isset() condition

$mycontent='<input type="text" name="myfield" class="form-control"
    value="'.(isset($post['myfield']) ? $post['myfield'] : '').' "
    id="myfield">';

or you can use null coalescing operator (??)...

$mycontent='<input type="text" name="myfield" class="form-control"
    value="'.($post['myfield'] ?? '').' "
    id="myfield">';

PHP Shorthand for isset form POST value

You can define variables in beginning of your script before HTML output, for example:

$name = isset($_POST['submit']) ? $_POST['name'] : null;

in your html section you can print $name without worrying it was not defined

<p><input type="text" name="name" value="<?php echo $name ?>" /></p>

Also if $_POST['submit'] does not contain any value you are more likely to receive FALSE statement. To avoid such issues use array_key_exists

PHP: a short cut for isset and !empty?

You can use a simple function

function post_value_or($key, $default = NULL) {
    return isset($_POST[$key]) && !empty($_POST[$key]) ? $_POST[$key] : $default;
}

Then use:

$pg_title = post_value_or('pg_title');
// OR with a default
$pg_title = post_value_or('pg_title', 'No Title');

What is the PHP shorthand for: print var if var exist

For PHP >= 7.0:

As of PHP 7 you can use the null-coalesce operator:

$user = $_GET['user'] ?? 'guest';

Or in your usage:

<?= $myVar ?? '' ?>

For PHP >= 5.x:

My recommendation would be to create a issetor function:

function issetor(&$var, $default = null) {
    return isset($var) ? $var : $default;
}

This takes a variable as argument and returns it, if it exists, or a default value, if it doesn't. Now you can do:

echo issetor($myVar);

But also use it in other cases:

$user = issetor($_GET['user'], 'guest');

Simple PHP isset test

Remove the !. You don't want to negate the expression.

$friendid = isset($_GET['friendid']) ? $_GET['friendid'] : 'empty';

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