How to Round Up a Number to Nearest 10

How to round up a number to nearest 10?

floor() will go down.

ceil() will go up.

round() will go to nearest by default.

Divide by 10, do the ceil, then multiply by 10 to reduce the significant digits.

$number = ceil($input / 10) * 10;

Edit: I've been doing it this way for so long.. but TallGreenTree's answer is cleaner.

How to round an integer up or down to the nearest 10 using Javascript

Divide the number by 10, round the result and multiply it with 10 again, for example:

33 / 10 = 3.3
3.3 rounded = 3
3 × 10 = 30

console.log(Math.round(prompt('Enter a number', 33) / 10) * 10);

How to round up to nearest 10 or 100 or x

Please try this formula

System.out.println(Math.ceil(x*Math.pow(10, -Math.floor(Math.log10(x)))) / Math.pow(10, -Math.floor(Math.log10(x))) ) ;
You can try this formula online.

class Main {
    public static void niceround(double x) {
        System.out.println(x+" to " + Math.ceil(x * Math.pow(10, -Math.floor(Math.log10(x)))) / Math.pow(10, -Math.floor(Math.log10(x))));
    }
    public static void main(String[] args) {
        niceround(0.0322);
        niceround(3.22);
        niceround(32.2);
        niceround(42.2);
        niceround(422.2);
    }
}

test

/usr/lib/jvm/java-1.8.0-openjdk-amd64/bin/java -agentlib:jdwp=transport=dt_socket,address=127.0.0.1:36808,suspend=y,server=n -Dfile.encoding=UTF-8 -classpath /usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/charsets.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/cldrdata.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/dnsns.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/icedtea-sound.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/jaccess.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/localedata.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/nashorn.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/sunec.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/sunjce_provider.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/sunpkcs11.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/ext/zipfs.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/jce.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/jsse.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/management-agent.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/resources.jar:/usr/lib/jvm/java-1.8.0-openjdk-amd64/jre/lib/rt.jar:/home/dac/proj/javatest2016/out/production/javatest2016:/home/dac/Downloads/idea-IU-145.972.3/lib/idea_rt.jar Main
Connected to the target VM, address: '127.0.0.1:36808', transport: 'socket'
0.0322 to 0.04
3.22 to 4.0
32.2 to 40.0
42.2 to 50.0
422.2 to 500.0
Disconnected from the target VM, address: '127.0.0.1:36808', transport: 'socket'

Process finished with exit code 0

How can I round a number down to the nearest 10?

You could use TRUNCATE function as follow:

SELECT TRUNCATE(819, -1);
SELECT TRUNCATE(812, -1);

Result:
810

Rounding a number to its nearest 10's place javascript

value = 2345;
 log_10 =  parseInt(Math.log(value) / Math.log(10));
                      basePower =  Math.pow(10, log_10); 
                      result = ((((value/basePower)).toFixed(0))* basePower); 
                      alert(result);

How to round up number to nearest 100/1000 depending on number, in JavaScript?

You could take the logarithm of ten and round up the value for getting the value.

function roundup(v) {    return Math.pow(10, Math.ceil(Math.log10(v)));}
console.log(roundup(87));   //   100console.log(roundup(776));  //  1000console.log(roundup(2333)); // 10000

How to Round Up a Number to Nearest 10