Create or write/append in text file
Try something like this:
$txt = "user id date";
$myfile = file_put_contents('logs.txt', $txt.PHP_EOL , FILE_APPEND | LOCK_EX);
How to append text to an existing file in Java?
Are you doing this for logging purposes? If so there are several libraries for this. Two of the most popular are Log4j and Logback.
Java 7+
For a one-time task, the Files class makes this easy:
try {
Files.write(Paths.get("myfile.txt"), "the text".getBytes(), StandardOpenOption.APPEND);
}catch (IOException e) {
//exception handling left as an exercise for the reader
}
Careful: The above approach will throw a NoSuchFileException
if the file does not already exist. It also does not append a newline automatically (which you often want when appending to a text file). Another approach is to pass both CREATE
and APPEND
options, which will create the file first if it doesn't already exist:
private void write(final String s) throws IOException {
Files.writeString(
Path.of(System.getProperty("java.io.tmpdir"), "filename.txt"),
s + System.lineSeparator(),
CREATE, APPEND
);
}
However, if you will be writing to the same file many times, the above snippets must open and close the file on the disk many times, which is a slow operation. In this case, a BufferedWriter
is faster:
try(FileWriter fw = new FileWriter("myfile.txt", true);
BufferedWriter bw = new BufferedWriter(fw);
PrintWriter out = new PrintWriter(bw))
{
out.println("the text");
//more code
out.println("more text");
//more code
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
Notes:
- The second parameter to the
FileWriter
constructor will tell it to append to the file, rather than writing a new file. (If the file does not exist, it will be created.) - Using a
BufferedWriter
is recommended for an expensive writer (such asFileWriter
). - Using a
PrintWriter
gives you access toprintln
syntax that you're probably used to fromSystem.out
. - But the
BufferedWriter
andPrintWriter
wrappers are not strictly necessary.
Older Java
try {
PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("myfile.txt", true)));
out.println("the text");
out.close();
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
Exception Handling
If you need robust exception handling for older Java, it gets very verbose:
FileWriter fw = null;
BufferedWriter bw = null;
PrintWriter out = null;
try {
fw = new FileWriter("myfile.txt", true);
bw = new BufferedWriter(fw);
out = new PrintWriter(bw);
out.println("the text");
out.close();
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
finally {
try {
if(out != null)
out.close();
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
try {
if(bw != null)
bw.close();
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
try {
if(fw != null)
fw.close();
} catch (IOException e) {
//exception handling left as an exercise for the reader
}
}
Writing to a new file if it doesn't exist, and appending to a file if it does
It's not clear to me exactly where the high-score that you're interested in is stored, but the code below should be what you need to check if the file exists and append to it if desired. I prefer this method to the "try/except".
import os
player = 'bob'
filename = player+'.txt'
if os.path.exists(filename):
append_write = 'a' # append if already exists
else:
append_write = 'w' # make a new file if not
highscore = open(filename,append_write)
highscore.write("Username: " + player + '\n')
highscore.close()
Writing a new and appending a file in PHP without erasing contents
Simply:
file_put_contents($filename,$songName.$newLine,FILE_APPEND);
Takes care of opening, writing to, and closing the file. It will even create the file if needed! (see docs)
If your new lines aren't working, the issue is with your $newLine
variable, not the file append operations. One of the following will work:
$newLine = PHP_EOL; << or >> $newLine = "\r\n";
JavaScript: Writing & appending text files from After Effects
To append the file it needs to pass the append mode...
reportFile.open("a");
How do I append to a file?
Set the mode in open()
to "a"
(append) instead of "w"
(write):
with open("test.txt", "a") as myfile:
myfile.write("appended text")
The documentation lists all the available modes.
How do I append text to a file with python?
For Append File:
with open("newfile.txt", "a+") as file:
file.write("I am adding in more lines\n")
file.write("And more…")
For Read File:
with open('newfile.txt') as f:
lines = f.readlines()
print(lines)
unable to write and append the text file android
after long work finally i found your solution, just implement below code it will help you..
public static void writefile(String text )
{
File externalStorageDir = new File (Environment.getExternalStorageDirectory().getAbsolutePath() + "/Download/eyedebug/" );
String fileName= System.currentTimeMillis() + ".txt" ;
boolean statement = externalStorageDir.exists() && externalStorageDir.isDirectory();
if(!statement) {
// do something here
externalStorageDir.mkdirs();
System.out.println("file 1");
}
File myFile = new File(externalStorageDir.getAbsolutePath() , fileName );
if(!myFile.exists()){
try {
myFile.createNewFile();
System.out.println("file 2");
}
catch (IOException e)
{
e.printStackTrace();
}
}
try
{
FileWriter fileWritter = new FileWriter(myFile,true);
BufferedWriter bufferWritter = new BufferedWriter(fileWritter);
bufferWritter.append(text);
bufferWritter.newLine();
System.out.println("file 3");
bufferWritter.close();
}
catch (IOException e)
{
e.printStackTrace();
}
}
Related Topics
Which $_Server Variables Are Safe
How to Insert Element into Arrays At Specific Position
How to Check If an Email Address Is Real or Valid Using PHP
What's the Deal With a Leading Underscore in PHP Class Methods
Check If a User/Guest Has Purchased Specific Products in Woocommerce
Formatting Datetime Object, Respecting Locale::Getdefault()
Ping Site and Return Result in PHP
PHP List of Specific Files in a Directory
Pdo With Insert into Through Prepared Statements
How to Upload & Save Files With Desired Name
Accessing Outside Variable Using Anonymous Function as Params
Passing JavaScript Array to PHP Through Jquery $.Ajax