Sed Search a Range and Print First Set

sed search a range and print first set

awk  '/myname/{if(b) exit; else b=1}1' filename

$ cat temp.txt
myname
_       something
_       something
_       something
myname
_       something
_       something
myname
_       something

$ awk  '/myname/{if(b) exit; else b=1}1' temp.txt
myname
_       something
_       something
_       something

Using sed to print range when pattern is inside the range?

You haven't said what an error message looks like, so I'll assume it contains the word "ERROR":

sed -n '/^MSG.*ERROR/{H;g;N;p;};/^DURATION/{s/.*//;h;d;};H' < logname

(I wish there were a tidier way to purge the hold space. Anyone?...)

How to print a range of lines with sed except the one matching the range-end pattern?

There might be better ways but I could come up with this sed 1 liner:

sed -rn '/ABC/,/^[^+]/{/(ABC|^\+)/!d;p;}' file

Another sed 1 liner is

sed -n '/ABC/,/^[^+]/{x;/^$/!p;}' file

One more sed 1 liner (and probably better)

sed -n '/ABC/I{h;:A;$!n;/^+/{H;$!bA};g;p;}' file

get range out using sed or awk, only if given pattern match

$ awk 'last~/START/ && /LINUX/ {print last; f=1} f{print} /END/{f=0} {last=$0}' file
START
OS:: LINUX
Release: xxx
Version: xxx
END

This approach will work even if there are lines in the input that are outside of START-END blocks.

How it works

last~/START/ && /LINUX/ {print last; f=1}
If the last line matches START and the current line matches LINUX, then print the last line and set variable f to 1.
f{print}
If f is nonzero, print the current line.
/END/{f=0}
If the current line matches END, the set f to zero.
last=$0
Save the current line in the variable last.

How can I extract a predetermined range of lines from a text file on Unix?

sed -n '16224,16482p;16483q' filename > newfile

From the sed manual:

p -
Print out the pattern space (to the standard output). This command is usually only used in conjunction with the -n command-line option.

n -
If auto-print is not disabled, print the pattern space, then, regardless, replace the pattern space with the next line of input. If
there is no more input then sed exits without processing any more
commands.

q -
Exit sed without processing any more commands or input.
Note that the current pattern space is printed if auto-print is not disabled with the -n option.

and

Addresses in a sed script can be in any of the following forms:

number
Specifying a line number will match only that line in the input.

An address range can be specified by specifying two addresses
separated by a comma (,). An address range matches lines starting from
where the first address matches, and continues until the second
address matches (inclusively).

sed — joining a range of selected lines

One way using GNU sed:

sed -n '/begin/,/end/ { H;g; s/^\n//; /end/s/\n/ /gp }' file.txt

sed, awk or perl: Pattern range match, print 45 lines then add record delimiter

I think I understand what you want. Not sure about the bit about pull each record by pattern range. Is #matchee always followed by a blank line and then the department line? So in fact record number 2?

This Perl fragment does what I understand you need.

If you prefer you can put the input file on the command line and drop the open call. Then the loop would have to be while (<>) { ... }.

Let us know if this is right so far, and what more you need from it.

use strict;
use warnings;

open my $fh, '<', 'mess-o-records.txt' or die $!;

my $count = 0;

while (<$fh>) {
  if (/^#matchee/) {
    print;
    $count = 0;
  }
  else {
    print if $count++ < 45;
  }
}

Sed Search a Range and Print First Set