Find Ip Address of My System for a Particular Interface with Shell Script (Bash)

Linux bash script to extract IP address

To just get your IP address:

echo `ifconfig eth0 2>/dev/null|awk '/inet addr:/ {print $2}'|sed 's/addr://'`

This will give you the IP address of eth0.

Edit: Due to name changes of interfaces in recent versions of Ubuntu, this doesn't work anymore. Instead, you could just use this:

hostname --all-ip-addresses or hostname -I, which does the same thing (gives you ALL IP addresses of the host).

find ip address of my system for a particular interface with shell script (bash)

Let's clean up your code first. You don't need chains of a dozen different commands and pipes when you're already using awk. This:

wifiip=$(ip addr | grep inet | grep wlan0 | awk -F" " '{print $2}'| sed -e 's/\/.*$//')

can be written simply as this:

wifiip=$(ip addr | awk '/inet/ && /wlan0/{sub(/\/.*$/,"",$2); print $2}')

but your whole script can be written as just one awk command.

I need you to update your question with some sample output of the ip addr command, the output you want from the awk command given that input, and explain more clearly what you're trying to do in order to show you the correct way to write that but it might be something like this:

ip addr | awk '
/inet/ { ip[$NF] = $2; sub(/\/.*$/,"",ip[$NF]) }
END { print ( "eth0" in ip ? ip["eth0"] : ip["wlan0"] ) }
' > /home/pi/att/ip.txt

Find network interface by IP address - Linux/Bash

You should use this comand :

ifconfig | grep -B1 "inet addr:10.0.0.10" | awk '$1!="inet" && $1!="--" {print $1}'

Hope this help !

How to get the primary IP address of the local machine on Linux and OS X?

Use grep to filter IP address from ifconfig:

ifconfig | grep -Eo 'inet (addr:)?([0-9]*\.){3}[0-9]*' | grep -Eo '([0-9]*\.){3}[0-9]*' | grep -v '127.0.0.1'

Or with sed:

ifconfig | sed -En 's/127.0.0.1//;s/.*inet (addr:)?(([0-9]*\.){3}[0-9]*).*/\2/p'

If you are only interested in certain interfaces, wlan0, eth0, etc. then:

ifconfig wlan0 | ...

You can alias the command in your .bashrc to create your own command called myip for instance.

alias myip="ifconfig | sed -En 's/127.0.0.1//;s/.*inet (addr:)?(([0-9]*\.){3}[0-9]*).*/\2/p'"

A much simpler way is hostname -I (hostname -i for older versions of hostname but see comments). However, this is on Linux only.

Shell - Get interface name of IP address

You can parse the output of ip addr using e.g. awk to find the interface name that has a certain ip address. For example:

ip addr | awk -vtarget_addr=192.168.1.200 '
/^[0-9]+/ {
  iface=substr($2, 0, length($2)-1)
}

$1 == "inet" {
  split($2, addr, "/")
  if (addr[1] == target_addr) {
    print iface
  } 
}
'

This look for the interface with address 192.168.1.200. On my system, this will print:

vlan100

Because:

$ ip addr show vlan100
5: vlan100: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN group default qlen 1000
    link/ether 56:ba:dc:0f:73:69 brd ff:ff:ff:ff:ff:ff
    inet 192.168.1.200/32 brd 192.168.1.200 scope global noprefixroute vlan100
       valid_lft forever preferred_lft forever
    inet 192.168.1.169/24 brd 192.168.1.255 scope global dynamic noprefixroute vlan100
       valid_lft 47960sec preferred_lft 47960sec
    inet6 fe80::acb6:be79:224e:3062/64 scope link noprefixroute 
       valid_lft forever preferred_lft forever

How do I find my computer's IP address using the bash shell?

ifconfig en0 | grep inet | grep -v inet6

Output of above is expected to be in the following form:

inet 192.168.111.1 netmask 0xffffff00 broadcast 192.168.111.255

Add an awk statement to print the second column to avoid using cut (awk is a pretty standard unix tool):

ifconfig en0 | grep inet | grep -v inet6 | awk '{print $2}'

I use the following to get the current IP when on a LAN where the first few numbers of the IP are always the same (replace 192.168.111 with your own numbers):

ifconfig | grep 192.168.111 | awk '{print $2}'

To get the ip of another machine that you know the name of, try (replace hostname and 192.168.111 with your own values):

ping -c 1 hostname | grep 192.168.11 | grep 'bytes from' | awk '{print $4}' | sed 's/://g'

Efficient way to get your IP address in shell scripts

you can do it with just one awk command. No need to use too many pipes.

$ ifconfig | awk -F':' '/inet addr/&&!/127.0.0.1/{split($2,_," ");print _[1]}'

Parse ifconfig to get only my IP address using Bash

Well, after hours of struggling I finally got it right:

ifconfig en1 | awk '{ print $2}' | grep -E -o "([0-9]{1,3}[\.]){3}[0-9]{1,3}"

That last part I had missing is just grep a pattern of IP addresses from my list.

Get MAC address using shell script

Observe that the interface name and the MAC address are the first and last fields on a line with no leading whitespace.

If one of the indented lines contains inet addr: the latest interface name and MAC address should be printed.

ifconfig -a |
awk '/^[a-z]/ { iface=$1; mac=$NF; next }
    /inet addr:/ { print iface, mac }'

Note that multiple interfaces could meet your criteria. Then, the script will print multiple lines. (You can add ; exit just before the final closing brace if you always only want to print the first match.)

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