Get string character by index
The method you're looking for is charAt
. Here's an example:
String text = "foo";
char charAtZero = text.charAt(0);
System.out.println(charAtZero); // Prints f
For more information, see the Java documentation on String.charAt
. If you want another simple tutorial, this one or this one.
If you don't want the result as a char
data type, but rather as a string, you would use the Character.toString
method:
String text = "foo";
String letter = Character.toString(text.charAt(0));
System.out.println(letter); // Prints f
If you want more information on the Character
class and the toString
method, I pulled my info from the documentation on Character.toString.
How can I get a character in a string by index?
string s = "hello";
char c = s[1];
// now c == 'e'
See also Substring
, to return more than one character.
How to get char from string by index?
First make sure the required number is a valid index for the string from beginning or end , then you can simply use array subscript notation.
use len(s)
to get string length
>>> s = "python"
>>> s[3]
'h'
>>> s[6]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>> s[0]
'p'
>>> s[-1]
'n'
>>> s[-6]
'p'
>>> s[-7]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: string index out of range
>>>
How to get letter from String by index? C++
std::string
provides operator[]
to access a character by index:
https://en.cppreference.com/w/cpp/string/basic_string/operator_at
Example:
const std::string s("hello");
const char c = s[0];
// c is set to ‘h’
How to get the index of each character of a string from the end
int i=sc.indexOf(sc.charAt(sc.length()-1));
should probably be
int i=sc.lastIndexOf(sc.charAt(sc.length()-1));
How do I access a specific index in a String in java?
You are trying to access the String
's characters as if it was an array of characters. You should use the charAt
method instead:
char a = inputString.charAt(2);
In order for array access to work, you should first obtain the array of characters of the given String
:
char[] chars = inputString.toCharArray();
char a = chars[2];
This is useful when iterating over the characters of the String
.
Getting character at a particular index in a string c#
string myString = "HelloWorld";
char myChar = myString[index];
Syntax for Returning One Character of String by Index
I think you have multiple choises.
1) Use built-in string functions instead. You can use MID
function get get part of a string. So in your case something like "get one character from valPos + 1
from sReadLine
.
FOR i := 0 TO 20 DO
IF MID(sReadLine, 1, valPos + i) = '"' THEN
EXIT;
END_IF
valstring := CONCAT(STR1 := valstring, STR2 := MID(sReadLine, 1, valPos + i));
END_FOR
2) Convert the ASCII byte to string. In TwinCAT systems, there is a function F_ToCHR
. It takes a ASCII byte in and returns the character as string. I can't find something like that for Codesys, but i'm sure there would be a solution in some library. So please note that this won't work in Codesys without modifications:
FOR i := 0 TO 20 DO
IF F_ToCHR(sReadLine[valPos + i]) = '"' THEN
EXIT;
END_IF
valstring := CONCAT(STR1 := valstring, STR2 := F_ToCHR(sReadLine[valPos + i]));
END_FOR
3) The OSCAT library seems to have a CHR_TO_STRING function. You could use this instead of F_ToCHR in step 2.
4) You can use pointers to copy the ASCII byte to a string array (MemCpy) and add a string end character. This needs some knowledge of pointers etc. See Codesys forum for some example.
5) You can write a helper function similar to step 2 youself. Check the example from Codesys forums. That example doesn't include all characters so it needs to be updated. It's not quite elegant.
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