How to Format Date Time Object with Format Dd/Mm/Yyyy

convert datetime to date format dd/mm/yyyy

DateTime dt = DateTime.ParseExact(yourObject.ToString(), "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);

string s = dt.ToString("dd/M/yyyy", CultureInfo.InvariantCulture);

how to format String to Date with format dd-mm-yyyy in java

tl;dr

LocalDate
.parse( "2022-05-12" )
.format(
    DateTimeFormatter.ofPattern( "dd-MM-uuuu" )
)

12-05-2022

java.time

Use modern java.time classes. Never use the terrible Date, Calendar, SimpleDateFormat classes.

ISO 8601

Your input conforms to ISO 8601 standard format used by default in the java.time classes for parsing/generating text. So no need to specify a formatting pattern.

LocalDate

Parse your date-only input as a date-only object, a LocalDate.

String input = "2022-05-12" ;
LocalDate ld = LocalDate.parse( input ) ;

To generate text in your desired format, specify a formatting pattern.

DateTimeFormatter f = DateTimeFormatter.ofPattern( "dd-MM-uuuu" ) ;
String output = ld.format( f ) ;

Rather than hardcode a particular pattern, I suggest learning to automatically localize using DateTimeFormatter.ofLocalizedDate.

All this has been covered many many times already on Stack Overflow. Always search thoroughly before posting. Search to learn more.

Why is it not possible to store DD-MM-YYYY format in date format?

Following the format of the solutions you have tried, a correct way to do it (not the most efficient) is:

import datetime

df["Date"] = [datetime.datetime.strptime(s, '%Y-%m-%d').strftime('%d-%m-%Y') for s in df["Date"]]

If you need more efficiency in the solution, the ideal would be to use vectorized operations, for example:

df['Date'] = pd.to_datetime(df['Date'])
df['Date'] = df["Date"].dt.strftime("%d-%m-%Y")

Or in a single line:

df['Date'] = pd.to_datetime(df['Date']).dt.strftime("%d-%m-%Y")

Need to convert datetime to dd/mm/yyyy

Yes, I would make df_sales_sum['Date'] a string: str(df_sales_sum['Date']). See if that helps. However, I'm not sure what df_sales_sum['Date'] output is.

df_date = str(df_sales_sum['Date'])

convert_date = df_date.strftime("%d/%m/%Y")

Good luck.

Convert date object in dd/mm/yyyy hh:mm:ss format

You can fully format the string as mentioned in other posts. But I think your better off using the locale functions in the date object?

var d = new Date("2017-03-16T17:46:53.677"); console.log( d.toLocaleString() ); 

Converting dd/mm/yyyy formatted string to Datetime

You need to use DateTime.ParseExact with format "dd/MM/yyyy"

DateTime dt=DateTime.ParseExact("24/01/2013", "dd/MM/yyyy", CultureInfo.InvariantCulture);

Its safer if you use d/M/yyyy for the format, since that will handle both single digit and double digits day/month. But that really depends if you are expecting single/double digit values.

---

Your date format day/Month/Year might be an acceptable date format for some cultures. For example for Canadian Culture en-CA DateTime.Parse would work like:

DateTime dt = DateTime.Parse("24/01/2013", new CultureInfo("en-CA"));

Or

System.Threading.Thread.CurrentThread.CurrentCulture = new CultureInfo("en-CA");
DateTime dt = DateTime.Parse("24/01/2013"); //uses the current Thread's culture

Both the above lines would work because the the string's format is acceptable for en-CA culture. Since you are not supplying any culture to your DateTime.Parse call, your current culture is used for parsing which doesn't support the date format. Read more about it at DateTime.Parse.

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Another method for parsing is using DateTime.TryParseExact

DateTime dt;
if (DateTime.TryParseExact("24/01/2013", 
                            "d/M/yyyy", 
                            CultureInfo.InvariantCulture, 
                            DateTimeStyles.None,
    out dt))
{
    //valid date
}
else
{
    //invalid date
}

The TryParse group of methods in .Net framework doesn't throw exception on invalid values, instead they return a bool value indicating success or failure in parsing.

Notice that I have used single d and M for day and month respectively. Single d and M works for both single/double digits day and month. So for the format d/M/yyyy valid values could be:

• "24/01/2013"
• "24/1/2013"
• "4/12/2013" //4 December 2013
• "04/12/2013"

For further reading you should see: Custom Date and Time Format Strings

How to convert dd/mm/yyyy string into JavaScript Date object?

MM/DD/YYYY format

If you have the MM/DD/YYYY format which is default for JavaScript, you can simply pass your string to Date(string) constructor. It will parse it for you.

var dateString = "10/23/2015"; // Oct 23
var dateObject = new Date(dateString);
document.body.innerHTML = dateObject.toString();

Return dd-mm-yyyy from Date() object

im looking for 04-11-2012 date format

Using today's date (which as an ISO string is currently "2016-03-08T13:51:13.382Z"), you can do this:

new Date().toISOString().replace(/T.*/,'').split('-').reverse().join('-')

The output of this is:

-> "08-03-2016"

This:

1. Grabs the date.
2. Converts it to an ISO string.
3. Replaces the 'T' and everything after it.
4. Converts it into an array by splitting on any hyphen ('-') character. (["2016", "03", "08"])
5. Reverses the order of the array. (["08", "03", "2016"])
6. Joins the array back as a string, separating each value with a hyphen character.

---

Here is a demo using your date (2012-11-04T14:55:45.000Z) as input:

var input = "2012-11-04T14:55:45.000Z",    output;
output = new Date(input).toISOString().replace(/T.*/,'').split('-').reverse().join('-');
document.getElementById('input').innerHTML = input;document.getElementById('output').innerHTML = output;

<p><strong>Input:</strong> <span id=input></span></p><p><strong>Output:</strong> <span id=output></span></p>

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