Get Class by Name

Getting class by its name

use forName instead..

something like this..

 try {
    Class<?> act = Class.forName("com.bla.TestActivity");
 } catch (ClassNotFoundException e) {
        e.printStackTrace();
}

Java - get the current class name?

The "$1" is not "useless non-sense". If your class is anonymous, a number is appended.

If you don't want the class itself, but its declaring class, then you can use getEnclosingClass(). For example:

Class<?> enclosingClass = getClass().getEnclosingClass();
if (enclosingClass != null) {
  System.out.println(enclosingClass.getName());
} else {
  System.out.println(getClass().getName());
}

You can move that in some static utility method.

But note that this is not the current class name. The anonymous class is different class than its enclosing class. The case is similar for inner classes.

How to get a Class Object from the Class Name in Java

You can use:

Class c = Class.forName("com.package.MyClass");

And later instantiate an object:

Object obj = c.newInstance();

EDIT: This is just the simplest use case. As indicated in the comments, you will need to consider constructor arguments and exceptions thrown by the initialization process. The JavaDocs for newInstance has all the details.

Get class name using jQuery

After getting the element as jQuery object via other means than its class, then

var className = $('#sidebar div:eq(14)').attr('class');

should do the trick. For the ID use .attr('id').

If you are inside an event handler or other jQuery method, where the element is the pure DOM node without wrapper, you can use:

this.className // for classes, and
this.id // for IDs

Both are standard DOM methods and well supported in all browsers.

getting only name of the class Class.getName()

Class.getSimpleName()

How to get element by class name?

The name of the DOM function is actually getElementsByClassName, not getElementByClassName, simply because more than one element on the page can have the same class, hence: Elements.

The return value of this will be a NodeList instance, or a superset of the NodeList (FF, for instance returns an instance of HTMLCollection). At any rate: the return value is an array-like object:

var y = document.getElementsByClassName('foo');
var aNode = y[0];

If, for some reason you need the return object as an array, you can do that easily, because of its magic length property:

var arrFromList = Array.prototype.slice.call(y);
//or as per AntonB's comment:
var arrFromList = [].slice.call(y);

As yckart suggested querySelector('.foo') and querySelectorAll('.foo') would be preferable, though, as they are, indeed, better supported (93.99% vs 87.24%), according to caniuse.com:

• querySelector(all)
• getElementsByClassName
• Don't use w3schools to learn something
• Refer to MDN for accurate information

Get class name and package of VariableElement

You can use the VariableElements asType() method to get a TypeMirror object and then the toString() method should return a "source code" representation of the type. There's also some utility function in Types that can be used with TypeMirrors.

How to get class name of any java file

Well .java files need to have the same name as the class or enum within, so we could just use the file name:

public String getClass(File file){
  return removeExtension(file.getName());
}

removeExtension has many different ways of achieving, here is just one:

public static String removeExtension(String file){
  return file.replaceFirst("[.][^.]+$", "");
}

More here: How to get the filename without the extension in Java?

...the reason behind me wanting to do is is so that I can count the methods within the class.

OK, well this is not the way to do it, you should look into reflection: What is reflection and why is it useful?

Get the name of a Dart class as a Type or String

The class type can be used as a Type:

Type myType = MyClass;

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