How to Structure a Query to Give Me Only the Rows That Match All Values in a CSV List of Ids in T-Sql

How can I structure a query to give me only the rows that match ALL values in a CSV list of IDs in T-SQL

Use the below splitter function which returns an int column. So it's easy to check the count in the HAVING clause.

CREATE FUNCTION [dbo].[DelimitedParamParser]( @DelimitedIds VARCHAR(MAX), @Delimiter CHAR(1)) 
RETURNS @IdsTable 
TABLE ( Id INT ) 
AS BEGIN

DECLARE @Length INT,
        @Index INT,
        @NextIndex INT

SET @Length = DATALENGTH(@DelimitedIds)
SET @Index = 0
SET @NextIndex = 0

WHILE (@Length > @Index )
BEGIN
    SET @NextIndex = CHARINDEX(@Delimiter, @DelimitedIds, @Index)
    IF (@NextIndex = 0 ) SET @NextIndex = @Length + 2
        INSERT @IdsTable SELECT SUBSTRING( @DelimitedIds, @Index, @NextIndex - @Index )
    SET @index = @nextindex + 1
END
 RETURN
END

This works, keep in mind to give an extra comma at the end.

DECLARE @DELIMITER CHAR = ','
DECLARE @CSV_STRING VARCHAR(20) = '1,3,'

SELECT Distinct SUPER_HERO.NAME, SKILL.NAME
FROM 
    SUPER_HERO
    INNER JOIN SUPER_HERO_SKILL ON  SUPER_HERO_SKILL.SUPER_HERO_ID = SUPER_HERO.ID
    INNER JOIN SKILL ON SUPER_HERO_SKILL.SKILL_ID = SKILL.ID
    WHERE SUPER_HERO.ID IN
    (
    SELECT SUPER_HERO_SKILL.SUPER_HERO_ID   
    FROM 
        SUPER_HERO
        INNER JOIN SUPER_HERO_SKILL ON  SUPER_HERO_SKILL.SUPER_HERO_ID = SUPER_HERO.ID
        INNER JOIN SKILL ON SUPER_HERO_SKILL.SKILL_ID = SKILL.ID
        INNER JOIN DelimitedParamParser(@CSV_STRING, @DELIMITER) SPLIT  ON SPLIT.ID = SUPER_HERO_SKILL.SKILL_ID
    GROUP BY SUPER_HERO_SKILL.SUPER_HERO_ID
    HAVING COUNT(DISTINCT(SUPER_HERO_SKILL.SKILL_ID)) = (SELECT COUNT(DISTINCT(Id)) FROM DelimitedParamParser(@CSV_STRING, @DELIMITER))
    )

Turning a Comma Separated string into individual rows

You can use the wonderful recursive functions from SQL Server:

Sample table:

CREATE TABLE Testdata
(
    SomeID INT,
    OtherID INT,
    String VARCHAR(MAX)
);

INSERT Testdata SELECT 1,  9, '18,20,22';
INSERT Testdata SELECT 2,  8, '17,19';
INSERT Testdata SELECT 3,  7, '13,19,20';
INSERT Testdata SELECT 4,  6, '';
INSERT Testdata SELECT 9, 11, '1,2,3,4';

The query

WITH tmp(SomeID, OtherID, DataItem, String) AS
(
    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM Testdata
    UNION all

    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM tmp
    WHERE
        String > ''
)
SELECT
    SomeID,
    OtherID,
    DataItem
FROM tmp
ORDER BY SomeID;
-- OPTION (maxrecursion 0)
-- normally recursion is limited to 100. If you know you have very long
-- strings, uncomment the option

Output

 SomeID | OtherID | DataItem 
--------+---------+----------
 1      | 9       | 18       
 1      | 9       | 20       
 1      | 9       | 22       
 2      | 8       | 17       
 2      | 8       | 19       
 3      | 7       | 13       
 3      | 7       | 19       
 3      | 7       | 20       
 4      | 6       |          
 9      | 11      | 1        
 9      | 11      | 2        
 9      | 11      | 3        
 9      | 11      | 4

How can I SELECT rows with MAX(Column value), PARTITION by another column in MYSQL?

You are so close! All you need to do is select BOTH the home and its max date time, then join back to the topten table on BOTH fields:

SELECT tt.*
FROM topten tt
INNER JOIN
    (SELECT home, MAX(datetime) AS MaxDateTime
    FROM topten
    GROUP BY home) groupedtt 
ON tt.home = groupedtt.home 
AND tt.datetime = groupedtt.MaxDateTime

How to select records where their statuses are just in a set?

SELECT  ID
FROM    PersonStatus
GROUP   BY ID
HAVING  SUM(CASE WHEN statuss IN (0, 1, 2) THEN 1 ELSE 0 END) >= 1 AND
        SUM(CASE WHEN statuss NOT IN (0, 1, 2) THEN 1 ELSE 0 END) = 0

SQLFiddle Demo

MySQL in-operator must match all values?

SELECT * 
    FROM table1 
        INNER JOIN table2 
            ON table1.threadid=table2.threadid 
    WHERE table2.threadcontributor IN ('1','52512')
    GROUP BY table1.PrimaryKey
    HAVING COUNT(DISTINCT table2.threadcontributor) = 2

SQL: select sets containing exactly given members

from your phrase

I want to select groupids which has members m1,m2 but no other members

try this one, the idea behind is to count the total instances of records that match the condition and the where clause and that it is equal to the total number of records per group.

SELECT groupid
FROM table1 a
WHERE memberid IN ('m1','m2')
GROUP BY groupid
HAVING COUNT(*) = 
(
  SELECT COUNT(*)
  FROM table1 b
  WHERE b.groupid = a.groupid
  GROUP BY b.groupID
)

SQLFiddle Demo

SQL find sets with common members (relational division)

I think this should also work

select distinct g.GroupID, c.ClassID
from @Groups g
    left join @Classes c on g.TagID = c.TagID
where not exists (
    select *
    from @Groups g2
    where g2.GroupID = g.GroupID
        and g2.TagID not in (
            select TagID
            from @Classes c2
            where c2.ClassID = c.ClassID
        )
    ) or c.ClassID is null

SQL split values to multiple rows

If you can create a numbers table, that contains numbers from 1 to the maximum fields to split, you could use a solution like this:

select
  tablename.id,
  SUBSTRING_INDEX(SUBSTRING_INDEX(tablename.name, ',', numbers.n), ',', -1) name
from
  numbers inner join tablename
  on CHAR_LENGTH(tablename.name)
     -CHAR_LENGTH(REPLACE(tablename.name, ',', ''))>=numbers.n-1
order by
  id, n

Please see fiddle here.

If you cannot create a table, then a solution can be this:

select
  tablename.id,
  SUBSTRING_INDEX(SUBSTRING_INDEX(tablename.name, ',', numbers.n), ',', -1) name
from
  (select 1 n union all
   select 2 union all select 3 union all
   select 4 union all select 5) numbers INNER JOIN tablename
  on CHAR_LENGTH(tablename.name)
     -CHAR_LENGTH(REPLACE(tablename.name, ',', ''))>=numbers.n-1
order by
  id, n

an example fiddle is here.

How to concatenate text from multiple rows into a single text string in SQL Server

If you are on SQL Server 2017 or Azure, see Mathieu Renda answer.

I had a similar issue when I was trying to join two tables with one-to-many relationships. In SQL 2005 I found that XML PATH method can handle the concatenation of the rows very easily.

If there is a table called STUDENTS

SubjectID       StudentName
----------      -------------
1               Mary
1               John
1               Sam
2               Alaina
2               Edward

Result I expected was:

SubjectID       StudentName
----------      -------------
1               Mary, John, Sam
2               Alaina, Edward

I used the following T-SQL:

SELECT Main.SubjectID,
       LEFT(Main.Students,Len(Main.Students)-1) As "Students"
FROM
    (
        SELECT DISTINCT ST2.SubjectID, 
            (
                SELECT ST1.StudentName + ',' AS [text()]
                FROM dbo.Students ST1
                WHERE ST1.SubjectID = ST2.SubjectID
                ORDER BY ST1.SubjectID
                FOR XML PATH (''), TYPE
            ).value('text()[1]','nvarchar(max)') [Students]
        FROM dbo.Students ST2
    ) [Main]

You can do the same thing in a more compact way if you can concat the commas at the beginning and use substring to skip the first one so you don't need to do a sub-query:

SELECT DISTINCT ST2.SubjectID, 
    SUBSTRING(
        (
            SELECT ','+ST1.StudentName  AS [text()]
            FROM dbo.Students ST1
            WHERE ST1.SubjectID = ST2.SubjectID
            ORDER BY ST1.SubjectID
            FOR XML PATH (''), TYPE
        ).value('text()[1]','nvarchar(max)'), 2, 1000) [Students]
FROM dbo.Students ST2