Access Top N in Group

Top n records per group sql in access

I had a similar problem a year ago: Top 3 per group including 0

Using the same approach, this will return the latest three dates for each LoginID - you may get more than three records if there are tied dates for the same LoginID.

SELECT  PR1.LogInID, PR1.Score, PR1.[Date Taken]
FROM    Progress AS PR1
WHERE   PR1.[Date Taken] IN (
                        SELECT TOP 3 PR2.[Date Taken]
                        FROM    Progress PR2
                        WHERE   PR2.LoginID = PR1.LoginID
                        ORDER BY PR2.[Date Taken] DESC
                        )
ORDER BY    LoginID, [Date Taken]

Access top n in group

This should work for you. If it doesn't satisfy your requirements, post back what you need.
Your original desire was to have 25, so you'd simply modify the last clause to be HAVING COUNT(*) <= 25

SELECT  a.item, 
        a.category, 
        a.inventorycount, 
        COUNT(*) AS ranknumber
FROM inv AS a 
INNER JOIN inv AS b 
     ON (a.category = b.category) 
     AND (a.inventorycount <= b.inventorycount)
GROUP BY  a.category, 
          a.item, 
          a.inventorycount
HAVING COUNT(*) <= 2
ORDER BY a.category, COUNT(*) DESC

If you wanted to select more columns from the table, simply add them to the SELECT and `GROUP BY' clauses.

Only when you want to expand the "TOP n for each Category, foo, bar", then you would add those columns to the INNER JOIN clause as well.

--show the top 2 items for each category and year.
SELECT  a.item, 
        a.category, 
        a.year,
        a.inventorycount, 
        COUNT(*) AS ranknumber
FROM inv AS a 
INNER JOIN inv AS b 
     ON (a.category = b.category) 
     AND (a.year = b.year) 
     AND (a.inventorycount <= b.inventorycount)
GROUP BY  a.category, a.item, a.year, a.inventorycount
HAVING COUNT(*) <= 2
ORDER BY a.year, a.category, COUNT(*) DESC

MS Access Select top n query grouped by multiple fields

You can do something like this

SELECT StudentID, Year, Subject,  AVG(TestScore) AS AvgScore
  FROM
(
  SELECT StudentID, Year, Subject, TestScore
   FROM MyTable t
   WHERE TestID IN
  (
   SELECT TOP 3 TestID 
     FROM MyTable
    WHERE StudentID = t.StudentID
      AND Year = t.Year
      AND Subject = t.Subject
    ORDER BY TestScore DESC, TestID
  )
) q
 GROUP BY StudentID, Year, Subject
 ORDER BY StudentID, Year, Subject;

Sample output:

| STUDENTID | YEAR | SUBJECT | AVGSCORE |
|-----------|------|---------|----------|
|         1 | 2012 |       1 |       91 |
|         1 | 2012 |       2 |       84 |
|         2 | 2012 |       1 |       94 |
|         2 | 2012 |       3 |       95 |

Here is SQLFiddle demo.

Demo as usually is for SQL Server but expected to work in MS Access, maybe with minor syntactic tweaks

how to select top N in access report detail section or select top N in sql subquery

Try the following query as your report recordsource:

SELECT  TestTable.GroupByCol, TestTable.DetailColA
FROM TestTable 
WHERE TestTable.DetailColA IN 
  (SELECT TOP 2 DetailColA FROM TestTable AS TT 
   WHERE TT.GroupByCol=TestTable.GroupByCol 
   ORDER BY TT.DetailColA) 
ORDER BY TestTable.GroupByCol, TestTable.DetailColA

See Allen Browne's Subquery Basics for more information.

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EDIT: As you alluded to in your comment, this can also be written as follows:

SELECT a.GroupByCol, a.DetailColA, COUNT(*) As RankNumber
FROM TestTable AS a INNER JOIN TestTable AS b
  ON a.GroupByCol = b.GroupByCol
 AND a.DetailColA >= b.DetailColA
GROUP BY a.GroupByCol, a.DetailColA
HAVING COUNT(*)<=2
ORDER BY a.GroupByCol, a.DetailColA, COUNT(*) 

You would have to benchmark to be sure, but this second version is probably more efficient. Which is more readable is probably a matter of personal preference (I find the first version more intuitive and readable).

select top x by group in ms access

MsAccess can have a subquery as its select expression, which can be used to produce a limited rownumber:

SELECT *
FROM (
SELECT TblA.*, 
   (SELECT count(*) from Sheet1 TblB 
    where tblB.GROUP=tblA.GROUP and tblB.Index<=tblA.Index) as ROWNO
FROM Sheet1 TblA) Step1
where Step1.ROWNO<=Step1.A

Biggest caveat is that if two rows of the same group can have the same Index value.

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