String Concatenation Error

Concatenate string in #error preprocessor symbol

You can't do it with #error but it is possible with #pragma message

#define XSTR(x) #x
#define STR(x) XSTR(x)

#define N 10
#if N != 9
#pragma message "N= " STR(N)
#error See message above
#endif

Error in string Concatenation in Shell Scripting

The name of a variable can contain letters ( a to z or A to Z), numbers ( 0 to 9) or the underscore character ( _).

Shell does not require any variable declaration as in programming languages as C , C++ or java. So when you write $A_new shell consider A_new as a variable, which you have not assigned any value therefore it comes to be null.

To achieve what you mentioned use as :
${A}_new

Its always a good practice to enclose variable names in braces after $ sign to avoid such situation.

Syntax error when using string concatenation in function argument

This feature was added in PHP 5.6. The same rule applies to class propety declarations.

It is now possible to provide a scalar expression involving numeric
and string literals and/or constants in contexts where PHP previously
expected a static value, such as constant and property declarations
and default function arguments.

See: Constant expressions

Unexpected string concatenation

Try using a template literal.

ie.

const ANR = 'Animal Friend,ANR,ANP,$30'
const specialityPlates = [
  {
    cName: 'Environmental / Wildlife',
    oSubMenu: [{
      cName: `${ANR}`, // "Animal Friend,ANR,ANP,$30"
      cReturn: `${ANR}|27.00` // "Animal Friend,ANR,ANP,$30|27.00"
    }]
  }
]

Why am I getting this python concatenation error?

The problem you're having is caused by operator precedence.

The following line works because this is string literal concatenation, which has a higher precedence than the % operator.

print "%s" "/" "%s" "/" "%s" % (now.month, now.day, now.year)

The following does NOT work because the + operator has a lower precedence than the % operator.

print "%s" + "/" + "%s" + "/" + "%s" % (now.month, now.day, now.year)

To fix it, add parentheses to the concatenation so that it is executed first, like so:

print ("%s" + "/" + "%s" + "/" + "%s") % (now.month, now.day, now.year)

Don't understand this string concatenation error when dynamically making a filename

If the variable ID includes a \r character then you might get the output you show. Add another replace to replace “\r” with “” and you will get a better-looking (and valid) filename

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