Ruby Regular Expression to Match a Url

Ruby Regular expression to match a url

You can try this:

/https?:\/\/[\S]+/

The \S means any non-whitespace character.

(Rubular)

What is the ruby regex to get a specific part of this URL?

str = "http://www.amazon.it/Calvin-Klein-Deluxe-K0S21120--Orologio/dp/B003CP0V6S/ref=lp_1597641031_1_8?ie=UTF8&qid=1349983393&sr=1-8"
(match = str.match(/\/dp\/([^\/]*)/)) && match[1]
# => "B003CP0V6S"

Ruby - Regular Expression to allow any Non-ASCII - Chinese characters in URL

You may use

/\A(?:https?:\/\/)?(?!www\.[^\/]*\z)[\d\p{L}_.-]+\.[\p{L}.]{2,6}(?:\/[^\s\/]+)*\/?\z/

See the regex demo

NOTE: To match a whole string with a Ruby regex, you should use \A and \z, not ^ and $ that match start and end of any line. That is why the demo is different from the final regex posted.

Pattern details

\A - start of string
(?:https?:\/\/)? - an optional http:// or https://
(?!www\.[^\/]*\z) - the text that is immediately to the right cannot be www. and followed with any 0+ chars other than / up to the end of the string
[\d\p{L}_.-]+ - 1 or more digit, letter, _, . or - chars
\. - a dot
[\p{L}.]{2,6} - 2 to 6 letters or dots
(?:\/[^\s\/]+)* - 0 or more sequences of / and 1+ chars other than whitespace and /
\/? - an optional /
\z - end of string.

Regular Expression - matching file extension from a URL

Is your goal to get 'mp4'? Might consider not using a regex at all...

> require 'uri'
> uri = URI.parse('http://mtc.cdn.vine.co/r/videos/0DCB6FF2EF1179983941847883776_38a153447e7.1.5.3901866229871838946.mp4?versionId=.k9_w6W7t1Yr1KUCWRIm6AnYhSdOUz32')
=> #<URI::HTTP http://mtc.cdn.vine.co/r/videos/0DCB6FF2EF1179983941847883776_38a153447e7.1.5.3901866229871838946.mp4?versionId=.k9_w6W7t1Yr1KUCWRIm6AnYhSdOUz32>
> uri.path
=> "/r/videos/0DCB6FF2EF1179983941847883776_38a153447e7.1.5.3901866229871838946.mp4"
> File.extname(uri.path)
=> ".mp4"

Regex to match rails get index urls

You may use

/\Ahttp:\/\/localhost:3000\/v2\/manufacturers(?:\/?(?:\?\S+)?|\/1\/models\/?)?\z/

See the Rubular demo

Pattern details

\A - start of string
http:\/\/localhost:3000\/v2\/manufacturers - a http://localhost:3000/v2/manufacturers string
(?:\/?(?:\?\S+)?|\/1\/models)? - an optional sequence of:
- \/? - an optional / char
- (?:\?\S+)? - an optional sequence of ? and 1+ non-whitespace
- | - or
- \/1\/models\/? - /1/models string and an optional / at the end
\z - end of string.

Ruby Regex: Rejecting selected URLs

The following ruby code rejects all strings in the array containing cart, order or login.

urls.reject { |url| url[/(cart|order|login)/] }

A raw regular expression which excludes words will use negative look-arounds:

^((?!login|order|cart).)*$

See rubular.

For more information, see @Max's suggested reading at Regular expression to match a line that doesn't contain a word?

Ruby on Rails URL Validation (regex)

Your input ( http://trentscott.com) does not have a subdomain but the regex is checking for one.

domain_regex = /^((http|https):\/\/)[a-z0-9]*(\.?[a-z0-9]+)\.[a-z]{2,5}(:[0-9]{1,5})?(\/.)?$/ix

Update

You also don't need the ? after ((http|https):\/\/) unless the protocol is sometimes missing. I've also escaped . because that will match any character. I'm not sure what the grouping above is for, but here is a better version that supports dashes and groups by section

domain_regex = /^((http|https):\/\/) 
(([a-z0-9-\.]*)\.)?                  
([a-z0-9-]+)\.                        
([a-z]{2,5})
(:[0-9]{1,5})?
(\/)?$/ix

Need a regular expression for match a 'url' in 'img' tag

You can use an expression like this one:

<img.*?src=\\"(.+?)\\"

You'll need to use the global modifier for the regex to get all matches on several tags.
If you are testing one string at a time, it shouldn't be necessary.

Example at regex101

Ruby Regular Expression to Match a Url