Split the String to Get Only the First 5 Characters

Split the string to get only the first 5 characters

You can't be in multiple cwds simultaneously. To run the command for each directory that matches the pattern, you can use Dir#glob:

Dir.glob('/var/cache/acpchef/src/ap-kernelmodule-10*').each do |cwd|
  Mixlib::ShellOut.new("command run here", cwd: cwd).run_command
end

split string only on first instance of specified character

Use capturing parentheses:

'good_luck_buddy'.split(/_(.*)/s)
['good', 'luck_buddy', ''] // ignore the third element

They are defined as

If separator contains capturing parentheses, matched results are returned in the array.

So in this case we want to split at _.* (i.e. split separator being a sub string starting with _) but also let the result contain some part of our separator (i.e. everything after _).

In this example our separator (matching _(.*)) is _luck_buddy and the captured group (within the separator) is lucky_buddy. Without the capturing parenthesis the luck_buddy (matching .*) would've not been included in the result array as it is the case with simple split that separators are not included in the result.

We use the s regex flag to make . match on newline (\n) characters as well, otherwise it would only split to the first newline.

How to get first 5 characters from string

For single-byte strings (e.g. US-ASCII, ISO 8859 family, etc.) use substr and for multi-byte strings (e.g. UTF-8, UTF-16, etc.) use mb_substr:

// singlebyte strings
$result = substr($myStr, 0, 5);
// multibyte strings
$result = mb_substr($myStr, 0, 5);

Javascript How to get first three characters of a string

var str = '012123';var strFirstThree = str.substring(0,3);
console.log(str); //shows '012123'console.log(strFirstThree); // shows '012'

First entry from string split

If you need to extract the first (or nth) entry from each split, use:

word <- c('apple-orange-strawberry','chocolate')

sapply(strsplit(word,"-"), `[`, 1)
#[1] "apple"     "chocolate"

Or faster and more explictly:

vapply(strsplit(word,"-"), `[`, 1, FUN.VALUE=character(1))
#[1] "apple"     "chocolate"

Both bits of code will cope well with selecting whichever value in the split list, and will deal with cases that are outside the range:

vapply(strsplit(word,"-"), `[`, 2, FUN.VALUE=character(1))
#[1] "orange" NA

Strip all but first 5 characters - Python

A string in Python is a sequence type, like a list or a tuple. Simply grab the first 5 characters:

 some_var = 'AAAH8192375948'[:5]
 print some_var # AAAH8

The slice notation is [start:end:increment] -- numbers are optional if you want to use the defaults (start defaults to 0, end to len(my_sequence) and increment to 1). So:

 sequence = [1,2,3,4,5,6,7,8,9,10] # range(1,11)

 sequence[0:5:1] == sequence[0:5] == sequence[:5] 
 # [1, 2, 3, 4, 5]

 sequence[1:len(sequence):1] == sequence[1:len(sequence)] == sequence[1:]
 # [2, 3, 4, 5, 6, 7, 8, 9, 10]

 sequence[0:len(sequence):2] == sequence[:len(sequence):2] == sequence[::2]
 # [1, 3, 5, 7, 9]

strip removes a character or set of characters from the beginning and end of the string - entering a negative number simply means that you are attempting to remove the string representation of that negative number from the string.

Split a string only by first space in python

Just pass the count as second parameter to str.split function.

>>> s = "238 NEO Sports"
>>> s.split(" ", 1)
['238', 'NEO Sports']

split string only on first instance - java

string.split("=", limit=2);

As String.split(java.lang.String regex, int limit) explains:

The array returned by this method contains each substring of this string that is terminated by another substring that matches the given expression or is terminated by the end of the string. The substrings in the array are in the order in which they occur in this string. If the expression does not match any part of the input then the resulting array has just one element, namely this string.

The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter.

The string boo:and:foo, for example, yields the following results with these parameters:

Regex Limit    Result

:     2        { "boo", "and:foo" }
:     5        { "boo", "and", "foo" }
:    -2        { "boo", "and", "foo" }
o     5        { "b", "", ":and:f", "", "" }
o    -2        { "b", "", ":and:f", "", "" }
o     0        { "b", "", ":and:f" }

Split the String to Get Only the First 5 Characters