Getting Rails to Accept European Date Format (Dd/Mm/Yyyy)

Getting rails to accept European date format (dd/mm/yyyy)

It may be just a case of the due_at value being nil. In your case it's an empty string, but ignored because of the :reject_if option on accepts_nested_attributes_for, and so it remains as nil.

>> Date.strptime(nil, "%d/%m/%Y")
TypeError: can't dup NilClass

Take care of it with some conditional then.

self.due_at = Date.strptime(self.due_at,"%d/%m/%Y").to_time unless self.due_at.nil?

Default Date Format in Rails (Need it to be ddmmyyyy)

In your settings file: config/environment.rb"

my_date_formats = { :default => '%d/%m/%Y' } 

ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.merge!(my_date_formats) 

ActiveSupport::CoreExtensions::Date::Conversions::DATE_FORMATS.merge!(my_date_formats) 

source:
http://thedevelopercorner.blogspot.com/2009/03/change-default-date-format-in-ruby-on.html

How to change date format from mm/dd/yyyy to dd/mm/yyyy Ruby on Rails

Two steps:

• You need to convert your string into Date object. For that, use Date#strptime.
• You can use Date#strftime to convert the Date object into preferred format.

See implementation below:

str = '01/14/2018'

date = Date.strptime(str, '%m/%d/%Y')
 => #<Date: 2018-01-14 ((2458133j,0s,0n),+0s,2299161j)>

date.strftime('%d-%m-%Y')
 => "14-01-2018"

date.strftime('%Y-%m-%d')
 => "2018-01-14"

Displaying the date pattern string in Rails i18n localization

That won't work because that's not how the format is specified. For English, this is how the date formats are specified:

formats:
  default: "%Y-%m-%d"
  long: "%B %d, %Y"
  short: "%b %d"

Here are the docs for these percent placeholders in case you're curious.

To solve your problem, I'd create a date, localize it, and replace the parts:

date = Date.new(2000, 12, 31)
I18n.l(date).sub('2000', 'yyyy').sub('12', 'mm').sub('31', 'dd')
# => "yyyy-mm-dd"

Note that this might not work if the locale uses a 2 digit year format. Let's try it for some locales (using the default from rails-i18n):

def get_date_string(locale = I18n.current)
  date = Date.new(2000, 12, 31)
  I18n.l(date, locale: locale)
    .sub('2000', 'yyyy')
    .sub('12', 'mm')
    .sub('31', 'dd')
end

formats = %i[en en-US en-GB es de fr pt].map do |locale|
  [locale, get_date_string(locale)]
end.to_h

formats will be:

{
  :en=>"yyyy-mm-dd",
  :"en-US"=>"mm-dd-yyyy",
  :"en-GB"=>"dd-mm-yyyy",
  :es=>"dd/mm/yyyy",
  :de=>"dd.mm.yyyy",
  :fr=>"dd/mm/yyyy",
  :pt=>"dd/mm/yyyy"
}

How do I format a date to mm/dd/yyyy in Ruby?

The strftime method can be used to format times:

Time.now.strftime("%m/%d/%Y")

Rails convert date format

This is similar to Getting rails to accept European date format (dd/mm/yyyy)

In your model, create a setter method, where "my_date" is your database field.

def my_date=(val)
  Date.strptime(val, "%d/%m/%Y") if val.present?
end

Formatting Date/Time in Ruby to YYYY-MM-DD HH:MM:SS

You can use the Time#strftime method to format the time into a variety of different formats, including the one which you need. It takes a parameter which specifies the format of the date output. Look at the documentation for this method for more instructions about how to use it.

Time.now.strftime("%F %T")

The %F specifies that we would like the date in YYYY-MM-DD format. This is followed by a space, then the %T specifier, which produces a HH:MM:SS time output.

To incorporate this into your code:

"erstellzeit": "#{Time.now.strftime("%F %T")}"

Alternatively, if you're getting an additional +0000 output, try:

"erstellzeit": "#{Time.now.strftime("%F %H:%M:%S")}"

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