Regex for Matching All Words Between a Set of Curly Braces

Regex to match words inside two or three curly braces

Here is something that might work for you:

(?<!\{)\{\{(?:([^{}]+)|\{([^{}]+)})}}(?!})

See the online demo

• Words that are between exactly 2 curly brackets will be in group 1.
• Words that are between exactly 3 curly brackets will be in group 2.

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• (?<!\{) - Negative lookbehind for opening curly bracket.
• \{\{ - Two literal curly (opening) brackets.
• (?: - Open non-capture group.
  
  • ([^{}]+) - A 1st capture group holding 1+ non-opening/closing brackets.
  • | - Or:
  • \{([^{}]+)} - A 2nd capture group with leading and trailing brackets.
  • ) - Close non-capture group.
• }} - Two literal curly (closing) brackets.
• (?!}) - Negative lookahead for closing curly bracket.

Regex for matching all words between a set of curly braces

You're close, but using the wrong method:

sentence = "hello {name} is {thing}"

sentence.scan(/\{(.*?)\}/)
# => [["name"], ["thing"]]

Regex to get string between curly braces

If your string will always be of that format, a regex is overkill:

>>> var g='{getThis}';
>>> g.substring(1,g.length-1)
"getThis"

substring(1 means to start one character in (just past the first {) and ,g.length-1) means to take characters until (but not including) the character at the string length minus one. This works because the position is zero-based, i.e. g.length-1 is the last position.

For readers other than the original poster: If it has to be a regex, use /{([^}]*)}/ if you want to allow empty strings, or /{([^}]+)}/ if you want to only match when there is at least one character between the curly braces. Breakdown:

• /: start the regex pattern
  
  
  • {: a literal curly brace
    
    
    • (: start capturing
      
      
      • [: start defining a class of characters to capture
        
        
        • ^}: "anything other than }"
      • ]: OK, that's our whole class definition
      • *: any number of characters matching that class we just defined
    • ): done capturing
  • }: a literal curly brace must immediately follow what we captured
• /: end the regex pattern

How to match words in curly braces?

Using \w will not match a space. You can match the content between the {{ and }} using for example .+? and place the capturing group between the first and the second curly brace.

In the replacement use $1

{({.+?})}          

Regex demo

If you only want to match word characters with a single space between the words, you could use match 1+ word chars and repeat 0 or more times 1+ word chars preceded by a space:

{({\w+(?: \w+)*})}

Regex demo

Regex to match string between curly braces (that allows to escape them via 'doubling')

You can use

(?<!{)(?:{{)*{([^{}]*)}(?:}})*(?!})

See the .NET regex demo.

In C#, you can use

var results = Regex.Matches(text, @"(?<!{)(?:{{)*{([^{}]*)}(?:}})*(?!})").Cast<Match>().Select(x => x.Groups[1].Value).ToList();

Alternatively, to get full matches, wrap the left- and right-hand contexts in lookarounds:

(?<=(?<!{)(?:{{)*{)[^{}]*(?=}(?:}})*(?!}))

See this regex demo.
In C#:

var results = Regex.Matches(text, @"(?<=(?<!{)(?:{{)*{)[^{}]*(?=}(?:}})*(?!}))")
    .Cast<Match>()
    .Select(x => x.Value)
    .ToList();

Regex details

• (?<=(?<!{)(?:{{)*{) - immediately to the left, there must be zero or more {{ substrings not immediately preceded with a { char and then {
• [^{}]* - zero or more chars other than { and }
• (?=}(?:}})*(?!})) - immediately to the right, there must be }, zero or more }} substrings not immediately followed with a } char.

Regex for matching any content between curly brackets, except for single-digit numbers?

You have 2 parts of the pattern. To match what is in between except for when there is a single digit:

 (?<={)(?!\d})[^{}]+(?=})

The pattern matches

• (?<={) Assert { to the left
• (?!\d}) Assert not \d} to the right
• [^{}]+ Match any char except { or }
• (?=}) Assert } at the right

Regex demo

Regex match text followed by curly brackets

editor\s*{\s*(?:\"[a-z]*\"\s*\".*\"\s*)*\}

Demo

Also tested it in Notepad++ it works fine

Matching all contents between curly braces - Regex

You can use this recursive regex in PHP:

$regex = '/ { ( (?: [^{}]* | (?R) )* ) } /x';

RegEx Demo

get match of string using regex that has curly braces and replace all incl curly braces

Regular expressions should start and end with / instead of the normal string delimiters.

let link = 'https://example.org'let content = '<span>Some text {some text inside}</span>'content = content.replace(/\{([^}]+)\}/, `<a href="${link}" target="_blank" key="anchor">some text inside</a>`)console.log(content)

regex - extract strings between curly braces without the curly braces

We can use a regex lookaround to match the { as lookaround followed by one or more characters that are not a }.

stringr::str_extract(text_test, '(?<=\\{)[^\\}]+')
#[1] "function_name"  "function_title" "function_name" 

Regex matches one or more characters that are not a } ([^\\}]+) that follows a { (regex lookaround ((?<=\\{))

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In base R, we can use regmatches/regexpr

regmatches(text_test, regexpr("(?<=\\{)[^\\}]+", text_test, perl = TRUE))
#[1] "function_name"  "function_title" "function_name" 

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