R Ifelse Statement

If else statement with multiple conditions and 4 outcomes

I get "Occaisonal" using your code.

Your if statements are looking at logical vectors, but returning one value for ALL rows, for example:

df[,2] is the whole column: 0.50 0.11 0.23 0.06 0.36 0.19

df[,2]>mean(relabund) returns a logical vector of:

TRUE FALSE FALSE FALSE TRUE FALSE

by using && you are performing a logical comparison to two logical vectors. As these vectors aren't the same, you always get false:

df[,2]>mean(relabund) && df[,3]>mean(freq)

==

c(TRUE, FALSE, FALSE, FALSE, TRUE, FALSE) && c(FALSE, FALSE, TRUE, FALSE, TRUE, FALSE)

==

FALSE

Also, df$Classification sets the column to be the same value, i.e. it's working on the whole dataset rather than row by row. What you need to do it perform vector operations on each row.

Using dplyr you can get an easier to read answer (for some!)

library(tidyverse)

species <- c("a", "b", "c", "d", "e", "f")
relabund <- c(.5, .11, .23, .06, .36, .19) #relative abundance
freq <- c(6, 3, 20, 2, 11, 4) #number of sites species occurs at
df = data.frame(species, relabund, freq)

df %>%
mutate(classify =
ifelse(freq < mean(freq) & relabund < mean(relabund),
"Rare",
ifelse(freq < mean(freq) & relabund > mean(relabund),
"Occaisonal",
ifelse(freq > mean(freq) & relabund < mean(relabund),
"Common",
ifelse(freq > mean(freq) & relabund > mean(relabund),
"Dominant",
"ERROR")))))

Using ifelse() statements to get objects of different classes in R

ifelse requires all the arguments to be same length. Here, it is not the case. Therefore, we need if/else

if(is.data.frame(mtcars) ) get(mtcars__string_object) else NA

-ouptut

                  mpg cyl  disp  hp drat    wt  qsec vs am gear carb
Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1
Duster 360 14.3 8 360.0 245 3.21 3.570 15.84 0 0 3 4
Merc 240D 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2
Merc 230 22.8 4 140.8 95 3.92 3.150 22.90 1 0 4 2
Merc 280 19.2 6 167.6 123 3.92 3.440 18.30 1 0 4 4
Merc 280C 17.8 6 167.6 123 3.92 3.440 18.90 1 0 4 4
Merc 450SE 16.4 8 275.8 180 3.07 4.070 17.40 0 0 3 3
Merc 450SL 17.3 8 275.8 180 3.07 3.730 17.60 0 0 3 3
Merc 450SLC 15.2 8 275.8 180 3.07 3.780 18.00 0 0 3 3
Cadillac Fleetwood 10.4 8 472.0 205 2.93 5.250 17.98 0 0 3 4
Lincoln Continental 10.4 8 460.0 215 3.00 5.424 17.82 0 0 3 4
Chrysler Imperial 14.7 8 440.0 230 3.23 5.345 17.42 0 0 3 4
Fiat 128 32.4 4 78.7 66 4.08 2.200 19.47 1 1 4 1
Honda Civic 30.4 4 75.7 52 4.93 1.615 18.52 1 1 4 2
Toyota Corolla 33.9 4 71.1 65 4.22 1.835 19.90 1 1 4 1
Toyota Corona 21.5 4 120.1 97 3.70 2.465 20.01 1 0 3 1
Dodge Challenger 15.5 8 318.0 150 2.76 3.520 16.87 0 0 3 2
AMC Javelin 15.2 8 304.0 150 3.15 3.435 17.30 0 0 3 2
Camaro Z28 13.3 8 350.0 245 3.73 3.840 15.41 0 0 3 4
Pontiac Firebird 19.2 8 400.0 175 3.08 3.845 17.05 0 0 3 2
Fiat X1-9 27.3 4 79.0 66 4.08 1.935 18.90 1 1 4 1
Porsche 914-2 26.0 4 120.3 91 4.43 2.140 16.70 0 1 5 2
Lotus Europa 30.4 4 95.1 113 3.77 1.513 16.90 1 1 5 2
Ford Pantera L 15.8 8 351.0 264 4.22 3.170 14.50 0 1 5 4
Ferrari Dino 19.7 6 145.0 175 3.62 2.770 15.50 0 1 5 6
Maserati Bora 15.0 8 301.0 335 3.54 3.570 14.60 0 1 5 8
Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2

Nested ifelse() statement in R not producing the desired results

Here is another possible option using rowSums:

df$newvar <- +(rowSums(df, na.rm = TRUE) * NA ^ (rowSums(!is.na(df)) == 0) > 0)

# var1 var2 var3 newvar
#1 NA 1 NA 1
#2 NA NA NA NA
#3 NA 0 NA 0
#4 0 0 0 0
#5 1 1 1 1


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