how to convert date and time from character to datetime type
As @Richard Scriven pointed out, you shouldn't be using as.Date
because it's not a datetime class. Here are a few different ways:
DateTime <- "2007-02-01 00:00:00"
DateTime2 <- "02/01/2007 00:06:10"
## default format Y-m-d H:M:S
> as.POSIXct(DateTime,tz=Sys.timezone())
[1] "2007-02-01 EST"
> as.POSIXlt(DateTime,tz=Sys.timezone())
[1] "2007-02-01 EST"
##
## specify format m/d/Y H:M:S
> as.POSIXct(DateTime2,format="%m/%d/%Y %H:%M:%S",tz=Sys.timezone())
[1] "2007-02-01 00:06:10 EST"
> as.POSIXlt(DateTime2,format="%m/%d/%Y %H:%M:%S",tz=Sys.timezone())
[1] "2007-02-01 00:06:10 EST"
##
## using lubridate
library(lubridate)
> ymd_hms(DateTime,tz=Sys.timezone())
[1] "2007-02-01 EST"
> mdy_hms(DateTime2,tz=Sys.timezone())
[1] "2007-02-01 00:06:10 EST"
You don't have to specify format=
for as.POSIXct
and as.POSIXlt
when you have the %Y-%m-%d %H:%M:%S
format. In other cases, like %m/%d/%Y %H:%M:%S
, you usually have to specify the format explicitly.
R: convert date from character to datetime
For me it works like this:
test <- "2016-04-10T12:21:25.4278624"
z <- as.POSIXct(test,format="%Y-%m-%dT%H:%M:%OS")
#output:
z
"2016-04-10 12:21:25 CEST"
The code is form here: converting datetime string to POSIXct date/time format in R
Trying to convert character to datetime using as_datetime() but getting a wrong format in R
You should change the format to match your data, your data is separated by dash (-), so the correct format would be %d-%m-%Y %R
or %d-%m-%Y %H:%M
. Notice that %R
is equivalent to %H:%M
.
library(lubridate)
as_datetime("01-07-2020 00:00", format = "%d-%m-%Y %R")
#> [1] "2020-07-01 UTC"
as_datetime("01-07-2020 17:59", format = "%d-%m-%Y %H:%M")
#> [1] "2020-07-01 17:59:00 UTC"
Learn more about date-time conversion format here
How to convert a character column to datetime in R
As suggested by akrun. You can use dmy_hms
function from lubridate
package.
Here is an example.
library(lubridate)
library(dplyr)
df1 <- df %>%
mutate(x = dmy_hms(x))
data:
df <- data.frame(x="10-MAR-21 08.07.14 PM")
Convert Character date/time with am and pm to date/time format
Make the following changes:
- use
%I
for the hour - use
%p
for the am/pm. - ensure that the format pattern is in the precise pattern of the data -- it's not in the question
- you likely want POSIXct, not POSIXlt
thus we use this format
as.POSIXct("1/29/20 3:43pm", format = "%m/%d/%y %I:%M%p")
## [1] "2020-01-29 15:43:00 EST"
R: convert character to date-time in this form: 2018-07-01 12
You can paste
the two columns and use as.POSIXct
specifying the formats.
df$V3 <- as.POSIXct(paste(df$V1, df$V2), format = '%Y-%m-%d %H', tz = 'UTC')
df$V3
#[1] "2018-07-01 12:00:00 UTC" "2018-07-01 13:00:00 UTC" "2018-07-01 14:00:00 UTC"
If you don't want to remember format use ymd_h
from lubridate
df$V3 <- lubridate::ymd_h(paste(df$V1, df$V2))
data
df <- structure(list(V1 = c("2018-07-01", "2018-07-01", "2018-07-01"
), V2 = 12:14), row.names = c(NA, -3L), class = "data.frame")
convert character column into datetime column in r , 04/19/19 08:46 this value is in character i need to get this in date time?
We can use as.POSIXct
df$Order.Date <- with(df, as.POSIXct(Order.Date, format = "%m/%d/%y %H:%M"))
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