Sort a List of Tuples by 2Nd Item (Integer Value)

Sort a list of tuples by 2nd item (integer value)

Try using the key keyword with sorted().

sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], 
       key=lambda x: x[1])

key should be a function that identifies how to retrieve the comparable element from your data structure. In your case, it is the second element of the tuple, so we access [1].

For optimization, see jamylak's response using itemgetter(1), which is essentially a faster version of lambda x: x[1].

Sorting a list of tuples by 2nd item not working in python

sorted returns a sorted version of the list you hand over.

The list itself is unmodified. You're always printing the unsorted list. Try:

sorted_list_1 = sorted(l, key=lambda x: x[0])
sorted_list_2 = sorted(l, key=lambda x: x[2])
print (sorted_list1, sorted_list2)

How to sort a list/tuple of lists/tuples by the element at a given index?

sorted_by_second = sorted(data, key=lambda tup: tup[1])

or:

data.sort(key=lambda tup: tup[1])  # sorts in place

The default sort mode is ascending. To sort in descending order use the option reverse=True:

sorted_by_second = sorted(data, key=lambda tup: tup[1], reverse=True)

or:

data.sort(key=lambda tup: tup[1], reverse=True)  # sorts in place

Sort by elements of a list of tuples

Hoo boy, this was a big XY problem. You want to sort by the third character of the second element of each tuple. Use the sorted built-in with its kwarg key.

lst = [('abc', 'bcd'), ('abc', 'zza')]
result = sorted(lst, key=lambda t: t[1][2])

key here accepts a function that is given each element in turn, and does something to it that is compared. In this case it returns the second element's third element (t[1][2]). Each element of the outer list is a tuple. Each tuple's second element exists in index 1, each second element's third character exists in index 2.

Sorting a list of tuples by the first value

The problem is that you have strings and so it's sorting them alphabetically. Convert to integers:

foundPlayers.append((int(row['Average PTS']), int(row['PlayerCode'])))

python sort list of tuples in list by value

This should do it:

l = [[('Armin', 1.0), ('Doris', 0.2240092377397959)], [('Benjamin', 1.0), ('Doris', 0.3090169943749474)], [('Caroline', 1.0), ('Benjamin', 0.2612038749637414)], [('Doris', 1.0), ('Benjamin', 0.3090169943749474)], [('Ernst', 1.0), ('Benjamin', 0.28989794855663564)]]

sorted(l, key=lambda x: x[1][1], reverse=True)

Explanation:
Passing the key parameter in sorted allows you to sort an object by a key that you specify. In this case, the key we wan to sort on is the second value in the second item of the list. Passing the reverse=True parameter sorts the list in descending order.

How to sort a list of tuples which elements are of mixed nature?

Use sorted with a key lambda:

sorted_list = sorted(mylist, key=lambda x: x[1])

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