Removing Numbers from String

Removing numbers from string

Would this work for your situation?

>>> s = '12abcd405'
>>> result = ''.join([i for i in s if not i.isdigit()])
>>> result
'abcd'

This makes use of a list comprehension, and what is happening here is similar to this structure:

no_digits = []
# Iterate through the string, adding non-numbers to the no_digits list
for i in s:
    if not i.isdigit():
        no_digits.append(i)

# Now join all elements of the list with '', 
# which puts all of the characters together.
result = ''.join(no_digits)

As @AshwiniChaudhary and @KirkStrauser point out, you actually do not need to use the brackets in the one-liner, making the piece inside the parentheses a generator expression (more efficient than a list comprehension). Even if this doesn't fit the requirements for your assignment, it is something you should read about eventually :) :

>>> s = '12abcd405'
>>> result = ''.join(i for i in s if not i.isdigit())
>>> result
'abcd'

Removing all numeric characters in a string, python

You can find the answer here
Removing numbers from string

From this answer:

comp_string = "xxf1,aff242342"
new_string = ''.join([i for i in comp_string if not i.isdigit()])

It creates a new string using .join from a list. That list is created using a list comprehension that iterates through characters in your original string, and excludes all digits.

How to remove numbers from string terms in a pandas dataframe

You can apply str.replace to the Name column in combination with regular expressions:

import pandas as pd

# Example DataFrame
df = pd.DataFrame.from_dict({'Name'  : ['May21', 'James', 'Adi22', 'Hello', 'Girl90'],
                             'Volume': [23, 12, 11, 34, 56],
                             'Value' : [21321, 12311, 4435, 32454, 654654]})

df['Name'] = df['Name'].str.replace('\d+', '')

print(df)

Output:

    Name   Value  Volume
0    May   21321      23
1  James   12311      12
2    Adi    4435      11
3  Hello   32454      34
4   Girl  654654      56

In the regular expression \d stands for "any digit" and + stands for "one or more".

Thus, str.replace('\d+', '') means: "Replace all occurring digits in the strings with nothing".

Remove numbers from string in dataframe in R

You can do this with gsub in base R :

df$ColA <- gsub('[0-9.]', '', df$ColA)
df

#  ColA ColB
#1    A  dff
#2    B  dfa
#3    C  dfd

data

df <- structure(list(ColA = c("A.12", "B.34", "C.545"), ColB = c("dff", 
"dfa", "dfd")), class = "data.frame", row.names = c(NA, -3L))

Removing numbers from string while keeping alphanumeric words

You can use regex to find runs of one or more digits \d+ between two word boundaries \b, and replace them with nothing.

>>> import re
>>> string = "Jobid JD123 has been abended with code 346"
>>> re.sub(r"\b\d+\b", "", string).strip()
'Jobid JD123 has been abended with code'

Note that the regex doesn't get rid of the trailing space (between "code" and the digits), so you need to strip() the result of the re.sub().

How to remove numbers from a string?

Very close, try:

questionText = questionText.replace(/[0-9]/g, '');

replace doesn't work on the existing string, it returns a new one. If you want to use it, you need to keep it!

Similarly, you can use a new variable:

var withNoDigits = questionText.replace(/[0-9]/g, '');

One last trick to remove whole blocks of digits at once, but that one may go too far:

questionText = questionText.replace(/\d+/g, '');

Strip Numbers From String in Python

Yes, you can use a regular expression for this:

import re
output = re.sub(r'\d+', '', '123hello 456world')
print output  # 'hello world'

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