How to Write Inline If Statement for Print

How to write inline if statement for print?

Python does not have a trailing if statement.

There are two kinds of if in Python:

1. if statement:

   if condition: statement
   if condition:
       block
   

2. if expression (introduced in Python 2.5)

   expression_if_true if condition else expression_if_false
   

And note, that both print a and b = a are statements. Only the a part is an expression. So if you write

print a if b else 0

it means

print (a if b else 0)

and similarly when you write

x = a if b else 0

it means

x = (a if b else 0)

Now what would it print/assign if there was no else clause? The print/assignment is still there.

And note, that if you don't want it to be there, you can always write the regular if statement on a single line, though it's less readable and there is really no reason to avoid the two-line variant.

How to write an inline IF statement in JavaScript?

You don't necessarily need jQuery. JavaScript alone will do this.

var a = 2;
var b = 3;    
var c = ((a < b) ? 'minor' : 'major');

The c variable will be minor if the value is true, and major if the value is false.

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This is known as a Conditional (ternary) Operator.

https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Operators/Conditional_Operator

how to print in single line with an inline if else statement in python 2.7

Put the comma at the end:

print 1 if x&i else 0,

You are using a conditional expression, of the form true_expr if condition_expr else false_expr, and the part before the if (true_expr) is part of that expression. you are printing the outcome of that expression.

Putting a simple if-then-else statement on one line

That's more specifically a ternary operator expression than an if-then, here's the python syntax

value_when_true if condition else value_when_false

Better Example: (thanks Mr. Burns)

'Yes' if fruit == 'Apple' else 'No'

Now with assignment and contrast with if syntax

fruit = 'Apple'
isApple = True if fruit == 'Apple' else False

vs

fruit = 'Apple'
isApple = False
if fruit == 'Apple' : isApple = True

Python inline if statement

This

twins[value] = twins[value] + [box] if value in twins else [box]

is functionally equivalent to this:

if value in twins:
    tmp = twins[value] + [box]
else:
    tmp = [box]
twins[value] = tmp

how can I print a message in if statement?

If you change the two if statement checks to something like this:

    if (option == "admin") {
        ...
    } else if (option == "client") {
        ...
    }

it might work a it better since at the moment it's checking against empty strings.

Python one line implementation of if-else

Using if and else inline like that only works with expressions. You can't put arbitrary statements. This is the kind of thing the Python designers intentionally don't want people doing, misusing language syntax to create dense, hard-to-read code.

The Zen of Python

Beautiful is better than ugly.

Explicit is better than implicit.

Simple is better than complex.
Complex is better than complicated.

Flat is better than nested.

Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.

Although practicality beats purity.

Errors should never pass silently.

Unless explicitly silenced.

In the face of ambiguity, refuse the temptation to guess.

There should be one—and preferably only one—obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.

Now is better than never.

Although never is often better than right now.

If the implementation is hard to explain, it's a bad idea.

If the implementation is easy to explain, it may be a good idea.

Namespaces are one honking great idea -- let's do more of those!

Use multiple lines:

if i % 2 != 0:
    print(i)
else:
    pass

Of course, the else isn't needed. If you remove it, I still recommend you leave the if block on two lines. There's no reason to compact it.

if i % 2 != 0:
    print(i)

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