How to Make a Grade Calculator in Python

How to make a grade calculator in Python

You need to compute percentage under the print case, this should get you what you want:

T_marks = 1100
data = {}
while True:
    ask = input("What do you want? ")
    if ask == "y":
        name = input("Enter your name: ")
        marks = int(input("Enter marks: "))
        data[name] = marks
    elif ask == "print":
        for (key,value) in data.items():
            # NOTE percentage is under the case when user asks for print
            percentage =(value / T_marks) * 100
            print(key,"::",value)
            if percentage > 90:
                print("Passed with A grade")
            elif percentage >= 70 and percentage < 90:
                print("Passed with B grade")
            elif percentage >= 60 and percentage < 70:
                print("Passed with C grade")
            elif percentage >= 50 and percentage < 60:
                print("passed with D Grade")
            else:
                print("You failed")
    else:
        print("Your work has ended")
        break

Also two hints: This code will output "You failed" if someone got a grade of 90. You need to set equality at 90 for one of the cases. Also python has simplified comparisons where and is not needed. Here is a simplified version, and corrected for case of 90 to get an A grade:

T_marks = 1100
data = {}
while True:
    ask = input("What do you want? ")
    if ask == "y":
        name = input("Enter your name: ")
        marks = int(input("Enter marks: "))
        data[name] = marks
    elif ask == "print":
        for (key,value) in data.items():
            percentage =(value / T_marks) * 100
            print(key,"::",value)
            if percentage >= 90:
                print("Passed with A grade")
            elif 90 > percentage >= 70:
                print("Passed with B grade")
            elif 70 > percentage >= 60:
                print("Passed with C grade")
            elif 60 > percentage >= 50:
                print("passed with D Grade")
            else:
                print("You failed")
    else:
        print("Your work has ended")
        break

Python - Grade Calculator

Again, just like other posts said, you have print twice. Also, your logic doesn't look right and here is something for your reference:

def ComputeGrade(score):

    if score > 0 and score <= 1:
        if score < 0.6:
            print("F")
        elif score < 0.7:
            print("D")
        elif score < 0.8:
            print("C")
        elif score < 0.9:
            print("B")
        else:
            print("A")
    else:
        print("Bad Score")

try:
   score = float(input("Enter Score: "))
   ComputeGrade(score)
except ValueError as e:
    print ("Bad Score")

Grade calculator range and ValueError - Python

Just for fun, let's make it a Match Case statement:

Since you only accept integers, we can take and assign score to input with :=, then check if it's valid with str.isnumeric. If that's true then we'll make score an integer := and check if it's between 0 and 100.

We'll change the input statement if they don't put valid input the first time around.

def grades():
    text = "Please enter your score between 0 and 100: "
    while True:
        if ((score := input(text)).isnumeric() and
            (score := int(score)) in range(0, 101)):
            break
        else:
            text = "Incorrect value. Please enter your score between 0 and 100: "
    match score:
        case x if x >= 90 : grade = 'A'
        case x if x >= 80 : grade = 'B'
        case x if x >= 70 : grade = 'C'
        case x if x >= 60 : grade = 'D'
        case x if x >= 50 : grade = 'E'
        case _ : grade = 'F'
    print(f'Grade: {grade}')

Please note that this will only work in Python 3.10 or greater.

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