Determine the Type of an Object

Determine the type of an object?

There are two built-in functions that help you identify the type of an object. You can use type() if you need the exact type of an object, and isinstance() to check an object’s type against something. Usually, you want to use isinstance() most of the times since it is very robust and also supports type inheritance.


To get the actual type of an object, you use the built-in type() function. Passing an object as the only parameter will return the type object of that object:

>>> type([]) is list
True
>>> type({}) is dict
True
>>> type('') is str
True
>>> type(0) is int
True

This of course also works for custom types:

>>> class Test1 (object):
pass
>>> class Test2 (Test1):
pass
>>> a = Test1()
>>> b = Test2()
>>> type(a) is Test1
True
>>> type(b) is Test2
True

Note that type() will only return the immediate type of the object, but won’t be able to tell you about type inheritance.

>>> type(b) is Test1
False

To cover that, you should use the isinstance function. This of course also works for built-in types:

>>> isinstance(b, Test1)
True
>>> isinstance(b, Test2)
True
>>> isinstance(a, Test1)
True
>>> isinstance(a, Test2)
False
>>> isinstance([], list)
True
>>> isinstance({}, dict)
True

isinstance() is usually the preferred way to ensure the type of an object because it will also accept derived types. So unless you actually need the type object (for whatever reason), using isinstance() is preferred over type().

The second parameter of isinstance() also accepts a tuple of types, so it’s possible to check for multiple types at once. isinstance will then return true, if the object is of any of those types:

>>> isinstance([], (tuple, list, set))
True

Determining type of an object in ruby

The proper way to determine the "type" of an object, which is a wobbly term in the Ruby world, is to call object.class.

Since classes can inherit from other classes, if you want to determine if an object is "of a particular type" you might call object.is_a?(ClassName) to see if object is of type ClassName or derived from it.

Normally type checking is not done in Ruby, but instead objects are assessed based on their ability to respond to particular methods, commonly called "Duck typing". In other words, if it responds to the methods you want, there's no reason to be particular about the type.

For example, object.is_a?(String) is too rigid since another class might implement methods that convert it into a string, or make it behave identically to how String behaves. object.respond_to?(:to_s) would be a better way to test that the object in question does what you want.

Finding the type of an object in C++

dynamic_cast should do the trick

TYPE& dynamic_cast<TYPE&> (object);
TYPE* dynamic_cast<TYPE*> (object);

The dynamic_cast keyword casts a datum from one pointer or reference type to another, performing a runtime check to ensure the validity of the cast.

If you attempt to cast to pointer to a type that is not a type of actual object, the result of the cast will be NULL. If you attempt to cast to reference to a type that is not a type of actual object, the cast will throw a bad_cast exception.

Make sure there is at least one virtual function in Base class to make dynamic_cast work.

Wikipedia topic Run-time type information

RTTI is available only for classes that are polymorphic, which means
they have at least one virtual method. In practice, this is not a
limitation because base classes must have a virtual destructor to
allow objects of derived classes to perform proper cleanup if they are
deleted from a base pointer.

Check if a value is an object in JavaScript

UPDATE:

This answer is incomplete and gives misleading results. For example, null is also considered of type object in JavaScript, not to mention several other edge cases. Follow the recommendation below and move on to other "most upvoted (and correct!) answer":

typeof yourVariable === 'object' && yourVariable !== null

Original answer:

Try using typeof(var) and/or var instanceof something.

EDIT: This answer gives an idea of how to examine variable's properties, but it is not a bulletproof recipe (after all there's no recipe at all!) for checking whether it's an object, far from it. Since people tend to look for something to copy from here without doing any research, I'd highly recommend that they turn to the other, most upvoted (and correct!) answer.

How to identify object types in java

You forgot the .class:

if (value.getClass() == Integer.class) {
System.out.println("This is an Integer");
}
else if (value.getClass() == String.class) {
System.out.println("This is a String");
}
else if (value.getClass() == Float.class) {
System.out.println("This is a Float");
}

Note that this kind of code is usually the sign of a poor OO design.

Also note that comparing the class of an object with a class and using instanceof is not the same thing. For example:

"foo".getClass() == Object.class

is false, whereas

"foo" instanceof Object

is true.

Whether one or the other must be used depends on your requirements.

How to determine an object's class?

if (obj instanceof C) {
//your code
}

How to find the type of an object in Go?

The most accurate way to check JS object's type?

The JavaScript specification gives exactly one proper way to determine the class of an object:

Object.prototype.toString.call(t);

http://bonsaiden.github.io/JavaScript-Garden/#types



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