Match exact string
Use the start and end delimiters: ^abc$
How to check if regex matches whole string in javascript?
You can either compare the length of the source to the match or compare the matched string to the source, if they are the same, you matched the entire string, and not just a part of it:
let source1 = "foo bar 12345";
let source2 = "foo bar 12345 foo";
let match1 = source1.match(/foo bar \d+/);
let match2 = source2.match(/foo bar \d+/);
console.log(match1[0] === source1);
console.log(match1[0].length === source1.length);
console.log(match2[0] === source2);
console.log(match2[0].length === source2.length);
How to match the whole string in RegEx?
For second task(number_number) you can use [^a-zA-Z]\d.*_\d.*, in you example asdf894343_84939, you get 894343_84939, or if you want to get only one digit - remove .* after \d.
In your first task, you also may use \d.*/\d[^\s], for example, if you have 34/45 sss - you get 34/45. If you want to get result from whole string you must use in you pattern: ^your pattern$
Checking whole string with a regex
\d+
matches any positive number of digits within your string, so it matches the first 78
and succeeds.
Use ^\d+$
.
Or, even better: "78.46.92.168:8000".isdigit()
RegEx to match full string
Use the end of line anchor $
:
^abc/$
This ensures that the exact string abc/
will be matched.
Regular expression for exact match of a string
if you have a the input password in a variable and you want to match exactly 123456 then anchors will help you:
/^123456$/
in perl the test for matching the password would be something like
print "MATCH_OK" if ($input_pass=~/^123456$/);
EDIT:
bart kiers is right tho, why don't you use a strcmp() for this? every language has it in its own way
as a second thought, you may want to consider a safer authentication mechanism :)
Regex matches parts of a string, but not whole string
I would say you need /^([a-zA-Z0-9-])+$/
. You want to match the whole string, not just a part, but you're missing the mark for the beginning of the string ^
.
^
and $
say between the beginning and the end of the string and ([a-zA-Z0-9-])+
says there can be one or more characters a-zA-Z0-9-
.
Your regexp matches everything which contains one or more characters a-zA-Z0-9-
before the end of the string no matter what's before.
You can test your regular expression on regex101.com (very good online tool for regular expression testing with explanation, reference etc.).
How do I match an entire string with a regex?
Try the following regular expression:
^Red October$
By default, regular expressions are case sensitive. The ^
marks the start of the matching text and $
the end.
Python regex match whole string only
You can use \Z
:
\Z
Matches only at the end of the string.
In [5]: re.match(r'\w+\Z', 'foo\n')
In [6]: re.match(r'\w+\Z', 'foo')
Out[6]: <_sre.SRE_Match object; span=(0, 3), match='foo'>
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