Check If a Word Is in a String in Python

Check if a word is in a string in Python

What is wrong with:

if word in mystring: 
   print('success')

How to check if a word is an English word with Python?

For (much) more power and flexibility, use a dedicated spellchecking library like PyEnchant. There's a tutorial, or you could just dive straight in:

>>> import enchant
>>> d = enchant.Dict("en_US")
>>> d.check("Hello")
True
>>> d.check("Helo")
False
>>> d.suggest("Helo")
['He lo', 'He-lo', 'Hello', 'Helot', 'Help', 'Halo', 'Hell', 'Held', 'Helm', 'Hero', "He'll"]
>>>

PyEnchant comes with a few dictionaries (en_GB, en_US, de_DE, fr_FR), but can use any of the OpenOffice ones if you want more languages.

There appears to be a pluralisation library called inflect, but I've no idea whether it's any good.

Python - Check if a word is in a string

What about to split the string and strip words punctuation, without forget the case?

w in [ws.strip(',.?!') for ws in p.split()]

Maybe that way:

def wordSearch(word, phrase):
    punctuation = ',.?!'
    return word in [words.strip(punctuation) for words in phrase.split()]

    # Attention about punctuation (here ,.?!) and about split characters (here default space)

Sample:

>>> print(wordSearch('Sea'.lower(), 'Do seahorses live in reefs?'.lower()))
False
>>> print(wordSearch('Sea'.lower(), 'Seahorses live in the open sea.'.lower()))
True

I moved the case transformation to the function call to simplify the code...

And I didn't check performances.

Checking if a word does not exist in a string Python

Checking if any element is not in message.
You could try this.

x = ['hello','there']
msg = 'hello sir'
wordsNotExistant = [words for words in msg.split(' ') if words not in x]

Output

['sir']

All the words in the given message that cannot be found in x will be appended to wordNotExistant

Check list of words in another string

if any(word in 'some one long two phrase three' for word in list_):

Determining if a string contains a word

words = 'blue yellow'

if 'blue' in words:
    print 'yes'
else:
    print 'no'

Edit

I just realized that nightly blues would contain blue, but not as a whole word. If this is not what you want, split the wordlist:

if 'blue' in words.split():
    …

How does Python check if a word is in a string?

You are not checking the condition right. You should rather

print('this' in res and 'that' in res and 'and' in res)

What you are checking is actually "true" in Python. Refer to this example below to find out

if 'this':
    print('found') # will print found

Check if string contains a word from dictionary python

You can use re:

import re
names = ["Joe", "Smith", "Nancy"]
string = "Her name was Nancy. His name was Smith"

result = re.findall('|'.join(names), string)
print(*result, sep='\n')

---

Nancy
Smith

---

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