Beautifulsoup Findall() Given Multiple Classes

Beautiful Soup find element with multiple classes

I'm guessing the soup in show = soup.find() is

source = requests.get(URL to get).text
soup = BeautifulSoup(source, 'lxml')

try:

show = soup.find('div', class_='action-link showPhonesLink').text

.text doesn't always work, but I've found the result doesn't really change without it.

i could give a more help answer if you could provide a little more details.

Include multiple class names in findAll in BeautifulSoup4

I would make a simple CSS selector:

soup.select('div[class="cb-lv-scrs-col cb-font-12 cb-text-complete"],div[class="cb-scag-mtch-status cb-text-inprogress"]')

but, I doubt you really need or should check all of the classes present on an element, would not that be sufficient:

soup.select('div.cb-text-complete,div.cb-text-inprogress')

Beautifulsoup multiple class selector

Use css selectors instead:

soup.select('div.A.B')

Python bs4 - find_all multiple tags and classes

If you have BS4 4.7.1 or above you can use css selector.

soup.select('a.full,td.fp.active')

OR

soup.select('.full,.fp.active')

Refering to two classes inside an Html tag using BeautifulSoup 4

The page is loaded dynamically, therefore if we call soup.prettify(), you see that all the desired output is under the class tab_item which includes tags that we don't want, and not under the class tab_item app_impression_tracked.

A different approach would be to use a CSS Selector to find all links under the NewReleasesRows ID (<div id="NewReleasesRows">).

To use a CSS Selector use the select() method instead of find_all() (in your example you have used find_all() instead of select())

import requests
from bs4 import BeautifulSoup

URL = "https://store.steampowered.com/tags/fr/RPG/"
soup = BeautifulSoup(requests.get(URL).content, "html.parser")

for tag in soup.select("#NewReleasesRows > a"):
    print(tag["href"])

Output:

https://store.steampowered.com/app/1433420/Hero_by_Chance/?snr=1_241_4_rpg_103
https://store.steampowered.com/app/1235140/Yakuza_Like_a_Dragon/?snr=1_241_4_rpg_103
https://store.steampowered.com/app/1445440/Blacksmith_of_the_Sand_Kingdom/?snr=1_241_4_rpg_103
...And on...

BeautifulSoup findAll tags with mutliple classes

Might be a bit slower, but uses the class_ selector:

divs = soup.find_all("div", class_="result-item standard") + soup.find_all("div", class_="result-item standard  basic ad")     
for div in divs:
    item = div.h2.a.text.split()
    item_year = item[0]
    item_make = item[1]

The syntax you are using is BS3, the syntax in this answer is BS4.

beautiful soup find_all, encompassing multiple class names

The function is given each class attribute value (str); then whole class attribute value (unless no previous call returned for the element). But None is passed is passed argument if there no class attribute.

So you need to check None.

Or for you case simple in should be enough:

for propbox in soup.find_all('div'):
    tester = propbox.find_all('td', {
        "class": lambda class_: class_ in ("class1", "class2")
    })
    # print(tester)

---

BTW, there's no contains method, but __contains__ method (in, membership test operator will use it):

>>> 'haystack'.contains('needle')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'str' object has no attribute 'contains'
>>> 'haystack'.__contains__('needle')
False
>>> 'needle' in 'haystack'
False

>>> 'haystack'.__contains__('hay')
True
>>> 'hay' in 'haystack'
True

---

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