How to Truncate the Time on a Datetime Object

How to truncate the time on a datetime object?

I think this is what you're looking for...

>>> import datetime
>>> dt = datetime.datetime.now()
>>> dt = dt.replace(hour=0, minute=0, second=0, microsecond=0) # Returns a copy
>>> dt
datetime.datetime(2011, 3, 29, 0, 0)

But if you really don't care about the time aspect of things, then you should really only be passing around date objects...

>>> d_truncated = datetime.date(dt.year, dt.month, dt.day)
>>> d_truncated
datetime.date(2011, 3, 29)

Truncate datetime object pandas

You simply need:

pd.to_datetime(df.date).dt.date

Output:

s1    2018-07-26
s2    2018-07-26
s3    2018-07-26
s4    2018-07-26
s5    2018-07-26
s6    2018-07-26
Name: date, dtype: object

How to truncate a time of datetime in python and wrt to postgresql?

You can format the datetime with f-strings or the .strftime method, but you probably shouldn't need to; depending on which framework/library you're using, it should convert the datetime automatically.

So the options, in the order of preference:

• Check your framework/library (you don't say which one you're using) for instructions on how to pass a datetime as a parameter; this is the best option by far.
• If that doesn't work, format the date as you might for printing it out, using either an f-string:
  

  f"{the_date:%Y-%m-%d %H:%M:%S}"
  

  or, using the strftime method
  

  the_date.strftime("%Y-%m-%d %H:%M:%S")
  

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Edit: The error you're seeing is not caused by the date; it's caused by using ? as the placeholder, while the library requires %s

db.execute("""INSERT INTO gcs_file_info_table (last_file_run, last_file_run_time) VALUES (%s, %s) """, values)

Remove time in date format in Python

You can use strftime to convert back in the format you need :

import datetime
s = "20200113"

temp = datetime.datetime.strptime(s, '%Y%m%d')
# 2020-01-13 00:00:00

final = temp.strftime('%Y-%m-%d')
print(final)
# 2020-01-13

truncate epoch time to start of hour / day

A day has 86400000 milliseconds.
One hour has 3600000 milliseconds.

Find the modulo and subtract it, so you'll obtain the start of the day, or hour.
You are essentially removing the remainder of milliseconds in the integer division, rounding down.

input_epoch = 1647548963623

truncate_day_epoch = input_epoch - (input_epoch % 86400000)

truncate_hour_epoch = input_epoch - (input_epoch % 3600000)

simple way to drop milliseconds from python datetime.datetime object

You can use datetime.replace() method -

>>> d = datetime.datetime.today().replace(microsecond=0)
>>> d
datetime.datetime(2015, 7, 18, 9, 50, 20)

How to remove time from date flutter

Please try below code:-

First you can create below method:-

String convertDateTimeDisplay(String date) {
    final DateFormat displayFormater = DateFormat('yyyy-MM-dd HH:mm:ss.SSS');
    final DateFormat serverFormater = DateFormat('dd-MM-yyyy');
    final DateTime displayDate = displayFormater.parse(date);
    final String formatted = serverFormater.format(displayDate);
    return formatted;
  }

Second you can call above method like below code:-

  String yourDate = '2019-10-22 00:00:00.000';
  convertDateTimeDisplay(yourDate);

Display Python datetime without time

print then.date()

What you want is a datetime.date object. What you have is a datetime.datetime object. You can either change the object when you print as per above, or do the following when creating the object:

then = datetime.datetime.strptime(when, '%Y-%m-%d').date()

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