(-5:Bad Argument) in Function 'Rectangle' - Can't Parse 'Pt1'. Sequence Item with Index 0 Has a Wrong Type

(-5:Bad argument) in function 'rectangle' - Can't parse 'pt1'. Sequence item with index 0 has a wrong type

The problem is that you are passing tuples with floats into the function's parameters as the points. Here is the error reproduced:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, c1, c2, (255, 0, 0), -1)

Output:

Traceback (most recent call last):
  File "C:/Users/User/Desktop/temp.py", line 9, in <module>
    cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle'
> Overload resolution failed:
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'rec'. Expected sequence length 4, got 2
>  - Can't parse 'rec'. Expected sequence length 4, got 2

And to fix it, simply use the int() wrapper around the coordinates:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

Can't parse 'center'. Sequence item with index 0 has a wrong type

The problem is just parsing the (x, y) or the (pts1[0][0], pts1[0][1]) to integers you just have to do the following (int(pts1[0][0]), int(pts1[0][1])) in the circle function

(-5:Bad argument) in function 'rectangle' - Can't parse 'pt1'. Sequence item with index 0 has a wrong type

The problem is that you are passing tuples with floats into the function's parameters as the points. Here is the error reproduced:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, c1, c2, (255, 0, 0), -1)

Output:

Traceback (most recent call last):
  File "C:/Users/User/Desktop/temp.py", line 9, in <module>
    cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle'
> Overload resolution failed:
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'rec'. Expected sequence length 4, got 2
>  - Can't parse 'rec'. Expected sequence length 4, got 2

And to fix it, simply use the int() wrapper around the coordinates:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

(-5:Bad argument) in function 'rectangle' - Can't parse 'pt1'. Sequence item with index 0 has a wrong type

The problem is that you are passing tuples with floats into the function's parameters as the points. Here is the error reproduced:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, c1, c2, (255, 0, 0), -1)

Output:

Traceback (most recent call last):
  File "C:/Users/User/Desktop/temp.py", line 9, in <module>
    cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle'
> Overload resolution failed:
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'rec'. Expected sequence length 4, got 2
>  - Can't parse 'rec'. Expected sequence length 4, got 2

And to fix it, simply use the int() wrapper around the coordinates:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

cv2.error : OpenCV(4.5.3) Error: bad argument & overload resolution failed in cv.line

The value assigned to pt1 and pt2 should not have a floating point.

So this is working fine.

import cv2
import numpy as np

h,w=100,100
im = ~np.zeros((h,w,3), np.uint8)

cv2.line(im, (0,10), (100,100),(0,0,255),2)
cv2.imshow('line',im)
cv2.waitKey(0)

Now if you change this line

cv2.line(im, (0,10), (100,100),(0,0,255),2)

to this

cv2.line(im, (0,10.1), (100,100),(0,0,255),2)
#OR
cv2.line(im, (0,10), (100,100.1),(0,0,255),2)

For the first one you get

Can't parse 'pt1'. Sequence item with index 1 has a wrong type

and for second one you get

Can't parse 'pt2'. Sequence item with index 1 has a wrong type

To fix this I can change

cv2.line(im, (0,10.1), (100,100),(0,0,255),2)

to

cv2.line(im, (0,int(10.1)), (100,100),(0,0,255),2)

How to solve cv2.error: OpenCV(4.5.4) :-1: error: (-5:Bad argument) in function 'imshow'

Output of detector.findHands(img) is a tuple. You should give second element of it as input to cv2.imshow():

from cvzone.HandTrackingModule import HandDetector
import cv2

cap = cv2.VideoCapture("https://192.168.178.49:8080/video")
detector = HandDetector(maxHands=1, detectionCon=0.7)

while True:
    success, img= cap.read()
    
    img = detector.findHands(img) 
    
    cv2.imshow("AI", img[1])
    cv2.waitKey(1)

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