Remove the Last Character from a String

How to remove the last character from a string?

replace will replace all instances of a letter. All you need to do is use substring():

public String method(String str) {
    if (str != null && str.length() > 0 && str.charAt(str.length() - 1) == 'x') {
        str = str.substring(0, str.length() - 1);
    }
    return str;
}

Delete the last two characters of the String

Subtract -2 or -3 basis of removing last space also.

 public static void main(String[] args) {
        String s = "apple car 05";
        System.out.println(s.substring(0, s.length() - 2));
    }

Output

apple car

Removing last character in C

Just set the last char to be '\0':

str[strlen(str)-1] = '\0';

In C, \0 indicates a string ending.

How can I remove the last character of a sentence in JavaScript?

Since the str.slice function returns the sliced part between two index as a substring, in your case, you should use str.slice(0,-1), that is equals to str.slice(0, str.length - 1). And it means that is going to return every character from zero index without the last character of the string passed.

function morseCode(str) {
    morseCode = {
    "A": ".- ",
    "B": "-... ",
    "C": "-.-. ",
    "D": "-.. ",
    "E": ". ",
    "F": "..-. ",
    "G": "--. ",
    "H": ".... ",
    "I": ".. ",
    "J": ".--- ",
    "K": "-.- ",
    "L": ".-.. ",
    "M": "-- ",
    "N": "-. ",
    "O": "--- ",
    "P": ".--. ",
    "Q": "--.- ",
    "R": ".-. ",
    "S": "... ",
    "T": "- ",
    "U": "..- ",
    "W": ".-- ",
    "X": "-..- ",
    "Y": "-.-- ",
    "Z": "--.. ",
    '1':'.---- ',
    '2':'..--- ',
    '3':'...-- ',
    '4':'....- ',
    '5':'..... ',
    '6':'-.... ',
    '7':'--... ',
    '8':'---.. ',
    '9':'----. ',}
    
    str = str.replace(/[!,?]/g , '');
    
    str = str.replace(/\s/g, '');
    
    return str.toUpperCase().split("").map(el => {
       return morseCode[el] ? morseCode[el] : el;
    }).join("").slice(0,-1);  // this returns the string without the last character.
    
};

How to remove first and last character of a string in Rust?

You can use the .chars() iterator and ignore the first and last characters:

fn rem_first_and_last(value: &str) -> &str {
    let mut chars = value.chars();
    chars.next();
    chars.next_back();
    chars.as_str()
}

It returns an empty string for zero- or one-sized strings and it will handle multi-byte unicode characters correctly. See it working on the playground.

Remove the last character of each string in array (JavaScript)

use a .map() to get a new array and for each item do a .slice(0,-1) to remove the last char.

const array = ['abcd', '1234', 'cde', 'dot.']
const withoutLastChar = array.map(string => string.slice(0, -1));

console.log(withoutLastChar);