PHP Date Function Seven Days Previous

PHP Date Function Seven days previous

Use the strtotime method provided by PHP.

date('Y-m-d', strtotime('-7 days'))

Thanks to @lonesomeday for pointing out my mistake in the comments ;)

php - add + 7 days to date format mm dd, YYYY

$date = "Mar 03, 2011";
$date = strtotime($date);
$date = strtotime("+7 day", $date);
echo date('M d, Y', $date);

Get Dates of the Last 7 Days in Array In Custom Format

function getLastNDays($days, $format = 'd/m'){
    $m = date("m"); $de= date("d"); $y= date("Y");
    $dateArray = array();
    for($i=0; $i<=$days-1; $i++){
        $dateArray[] = '"' . date($format, mktime(0,0,0,$m,($de-$i),$y)) . '"'; 
    }
    return array_reverse($dateArray);
}

Usage:

$arr = getLastNDays(7);

or

$arr = getLastNDays(7, 'd/m/Y');

Return current date plus 7 days

strtotime will automatically use the current unix timestamp to base your string annotation off of.

Just do:

$date = strtotime("+7 day");
echo date('M d, Y', $date);

Added Info For Future Visitors: If you need to pass a timestamp to the function, the below will work.

This will calculate 7 days from yesterday:

$timestamp = time()-86400;

$date = strtotime("+7 day", $timestamp);
echo date('M d, Y', $date);

generating dates of previous seven days in php

Easiest way would be to get a timestamp that corresponds to today, using the time() function ; and 7 times remove 1 day to that timestamp, each echoing the date that corresponds to that timestamp :

$timestamp = time();
for ($i = 0 ; $i < 7 ; $i++) {
    echo date('Y-m-d', $timestamp) . '<br />';
    $timestamp -= 24 * 3600;
}

Which will get you this output :

2010-02-25
2010-02-24
2010-02-23
2010-02-22
2010-02-21
2010-02-20
2010-02-19

Because a timestamp only represents the number of seconds since 1970-01-01, substracting one day to a timestamp means substracting 24*3600 seconds.

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Edit after the comments :

For month and weeks changes, this will still work : one day is still 24*3600 seconds.

For instance, if you test using this line instead of the first one I posted in my first example :

$timestamp = strtotime('2010-02-03');

You'll get this output :

2010-02-03
2010-02-02
2010-02-01
2010-01-31
2010-01-30
2010-01-29
2010-01-28

It changed of month fine.

For leap years, if I test using this :

$timestamp = strtotime('2008-03-03');

I get :

2008-03-03
2008-03-02
2008-03-01
2008-02-29
2008-02-28
2008-02-27
2008-02-26

Which looks fine, as there were 29 days in february 2008.

And if I test with :

$timestamp = strtotime('2009-03-03');

I get :

2009-03-03
2009-03-02
2009-03-01
2009-02-28
2009-02-27
2009-02-26
2009-02-25

Which looks fine too.

DateTime 7 days from now at 00:00

Just use DateTime and DateInterval.

Example:

$date = new DateTime();
$date->sub(new \DateInterval('P7D'));
echo $date->format('Y-m-d 00:00:00');

Finding last 7 working days in PHP

Finding holidays will be more complicated.
One solution can be like saving the holidays in advance and skip them if they comes in the condition.

One simple solution for your problem can be like this.

<?php

$holiday = array(
        '2017-12-16' => 'Victory Day of Bangladesh',
        '2017-12-25' => 'Christmas'
    );

$i = 0;
$work_day = '2017-12-26';
while($i != 7)
{
    $work_day = date('Y-m-d', strtotime('-1 day', strtotime($work_day)));
    $day_name = date('l', strtotime($work_day));

    if($day_name != 'Saturday' && $day_name != 'Sunday' && !isset($holiday[$work_day]))
    {
        echo $work_day."\n";
        $i++;
    }
}

?>

Checking if a date is within 7 days of the current time

if( strtotime($rows['Date']) > strtotime('-7 day') ) {
    echo '<div class="l-new"><a href="#"><!-- --></a></div>';
}

The strtotime('-7 day') part returns the time 7 days ago.

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