Pattern decoding
I don't know what would be your expected output, however I have converted/decoded your number pattern to a meaningful group/house/rooms format. any further "query" could be done on this content.
see below:
kent$ cat file
0 0
0 0
0 1
0 2
1 0
1 1
0 0
0 1
0 2
0 0
1 0
2 0
3 0
0 0
0 0
awk:
kent$ awk 'BEGIN{RS=""}
{ print "\ngroup "++g;
delete a;
for(i=1;i<=NF;i++) if(i%2) a[$i]++;
for(x in a) printf "House#: %s , Room(s): %s \n", x, a[x]; }' file
we get output:
group 1
House#: 0 , Room(s): 1
group 2
House#: 0 , Room(s): 3
House#: 1 , Room(s): 2
group 3
House#: 0 , Room(s): 3
group 4
House#: 0 , Room(s): 1
House#: 1 , Room(s): 1
House#: 2 , Room(s): 1
House#: 3 , Room(s): 1
group 5
House#: 0 , Room(s): 1
group 6
House#: 0 , Room(s): 1
note that the generated format could be changed to fit your "filter" or "query"
UPDATE
OP's comment:
I need to know, the number of the group(s) which have/has for example
1 house with one room. The output would be in the above case: 1, 5 ,6
as I said, based on your query criteria, we could adjust the awk output for next step. now I change the awk abovet to:
awk 'BEGIN{RS=""}
{print ""; gid=++g;
delete a;
for(i=1;i<=NF;i++) if(i%2) a[$i]++;
for(x in a) printf "%s %s %s\n", gid,x, a[x]; }' file
this will output:
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
6 0 1
the format is groupIdx houseIdx numberOfRooms
and there is a blank line between groups. we save the text above to a file named decoded.txt
so your query could be done on this text:
kent$ awk 'BEGIN{RS="\n\n"}{if (NF==3 && $3==1)print $1}' decoded.txt
1
5
6
the last awk line above means, print the group number, if room number ($3) = 1 and there is only one line in the group block.
Pattern of decoding instruction
The CPU's frontend can decode multiple (macro) instructions in one clock cycle. Each macro instruction decodes to 1 or more micro-ops (μops). What the 4-1-1 pattern means is that the first parallel decoder can handle a complex instruction that decodes to up to 4 μops. But the second and third parallel decoders can only handle instructions that decode to 1 μop each (if not satisfied, they don't consume the instruction).
The 5 instructions that decode to 2 μops will must be consumed by the first decoder, then the tail allows some parallelism.
2 2 2 2 2 1 1 1 (Macro-instruction stream, μops per instruction)
^ x x
4 1 1 (Decode cycle 0)
. 2 2 2 2 1 1 1
^ x x
4 1 1 (Decode cycle 1)
. . 2 2 2 1 1 1
^ x x
4 1 1 (Decode cycle 2)
. . . 2 2 1 1 1
^ x x
4 1 1 (Decode cycle 3)
. . . . 2 1 1 1
^ ^ ^
4 1 1 (Decode cycle 4)
. . . . . . . 1
^ x x
4 1 1 (Decode cycle 5)
. . . . . . . . (Instruction stream fully consumed)
Swift Catch Pattern that binds the error to a variable
The syntax used in a catch
line is exactly the same pattern syntax used in the case
of a switch
. If you know how to write a case
you know how to write a catch
.
So, for example, you complain:
} catch let decodingError is DecodingError { // THIS IS NOT VALID
Right. But this is valid:
} catch let decodingError as DecodingError {
Oh what a difference one letter makes.
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