How to Split a String into an Array of Characters

Split string into array of character strings

"cat".split("(?!^)")

This will produce

array ["c", "a", "t"]

How do I split a string into an array of characters?

You can split on an empty string:

var chars = "overpopulation".split('');

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If you just want to access a string in an array-like fashion, you can do that without split:

var s = "overpopulation";
for (var i = 0; i < s.length; i++) {
    console.log(s.charAt(i));
}

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You can also access each character with its index using normal array syntax. Note, however, that strings are immutable, which means you can't set the value of a character using this method, and that it isn't supported by IE7 (if that still matters to you).

var s = "overpopulation";

console.log(s[3]); // logs 'r'

Split string into array

Use the .split() method. When specifying an empty string as the separator, the split() method will return an array with one element per character.

entry = prompt("Enter your name")
entryArray = entry.split("");

Split string into string array of single characters

I believe this is what you're looking for:

char[] characters = "this is a test".ToCharArray();

How to split a string and store each character into an array

I wanted to check how many similar characters between search and
arr[i]

Then you can use strpbrk but somewhat reversed from how you attempted. man 3 strpbrk with declaration of

char *strpbrk(const char *s, const char *accept);

locates the first occurrence in the string s
of any of the bytes in the string accept.

So what you want do is simply loop with strpbrk and find out how many characters of search are common to arr[i]. Using a pointer makes that simple, e.g.

#include <stdio.h>
#include <string.h>

int main (void) {

    char search[] = "chzi",
        arr[][20] = {"cheang", "wai"};
    size_t n = sizeof arr / sizeof *arr;

    for (size_t i = 0; i < n; i++) {
        size_t count = 0;
        char *p = arr[i];
        while ((p = strpbrk (p, search)))
            count++, p++;
        printf ("%s contains %zu occurrence of characters in %s.\n",
                arr[i], count, search);
    }
}

Note above you simply use a pointer to arr[i] and then use strpbrk to locate the first character in search that occurs in arr[i]. You then increment the pointer to the next character in arr[i] (using p++;) and do it again until strpbrk returns NULL indicating there are no more character is arr[i] that match any of the characters in search, the code above does just this, e.g.

        char *p = arr[i];
        while ((p = strpbrk (p, search)))
            count++, p++;

which if you wanted to avoid using the comma operator would be:

        char *p = arr[i];
        while ((p = strpbrk (p, search))) {
            count++;
            p++;
        }

Example Use/Output

Running with your strings would result in:

$ ./bin/strpbrkchars
cheang contains 2 occurrence of characters in chzi.
wai contains 1 occurrence of characters in chzi.

Look things over and let me know if that is what you intended. You will need to add your probability code, but that is left to you.

How to split a string into an array of individual characters

Here is another option:

   Dim s As Variant
   s = "012345678901234"
   s = StrConv(s, vbUnicode)
   s = Split(s, vbNullChar)

s will contain an array of characters.

Java-Split characters from a String into an Array of Strings

How about this?

public class StringSplitter {
    public static void main(String[] args) {
        String str = new String("Welcome to Tutorialspoint.com and again some other random stuff in this string.");
        String[] result = new String[8];

        for (int i = 0; i < result.length; ++i) {
            result[i] = "";
        }

        char[] chars = str.toCharArray();
        for (int i = 0; i < chars.length; ++i) {
            result[i % result.length] += chars[i];
        }

        for (int i = 0; i < result.length; ++i) {
            System.out.println(result[i]);
        }
    }
}

Since your result array is already instantiated, it's safe to use the length property to initialize the elements to empty strings. Since you intend to process each character in the string, go ahead and just get it as an array, and then use the modulus operator to put each character into its proper place in the result array. As an added benefit, it's also safe against changing the length of the result array. Hard-coded loop sentinels are dangerous.

Output

Wtitdsemis
eoa. or nt
l lcam s r
cTsogertti
oupma auhn
mto ionfig
eoiantdfs.
 rnn ho  

How to split string with character \ - Javascript

Backslashes '\' escape the next character in the sequence. If you need the '\' in the string, your string will need to look like '\\op*Bw'

let s = '\\op*Bw'.split('');
console.log(s) // ['\', 'o', 'p', '*', 'B', 'w']

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