How to Remove Emoji Code Using JavaScript

How to remove emoji code using javascript?

The range you have selected is the Private Use Area, containing non-standard characters. Carriers used to encode emoji as different, inconsistent values inside this range.

More recently, the emoji have been given standardised 'unified' codepoints. Many of these are outside of the Basic Multilingual Plane, in the block U+1F300–U+1F5FF, including your example U+1F534 Large Red Circle.

You could detect these characters with [\U0001F300-\U0001F5FF] in a regex engine that supported non-BMP characters, but JavaScript's RegExp is not such a beast. Unfortunately the JS string model is based on UTF-16 code units, so you'd have to work with the UTF-16 surrogates in a regexp:

return this.replace(/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g, '')

However, note that there are other characters in the Basic Multilingual Plane that are used as emoji by phones but which long predate emoji. For example U+2665 is the traditional Heart Suit character ♥, but it may be rendered as an emoji graphic on some devices. It's up to you whether you treat this as emoji and try to remove it. See this list for more examples.

How can I remove the last emoji of a group of emojis in javascript?

Ok, here is how I solved it:

function deleteEmoji(emojiStr) {
    let emojisArray = emojiStr.match(/([\uD800-\uDBFF][\uDC00-\uDFFF])/g);
    emojisArray = emojisArray.splice(0, emojisArray.length - 1);
    return emojisArray.join("");
}
let emojitext = ";
console.log(deleteEmoji(emojitext));

Remove emoji but not non english chars

Here is a single pattern with a broad character range:

/[^ -\u2122]+ +| *[^ -\u2122]+/ug

My method is essentially ported from this php answer: https://stackoverflow.com/a/43106144/2943403

It will remove one or more emojis at a time and space characters on one side (but not both).

$('#submit').on('click', function() {  $("#after").html($('#before').val().replace(/[^ -\u2122]+ +| *[^ -\u2122]+/ug,''));});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script><textarea id="before" cols="75" rows="5">Sample emoji for test: ⛔️ Sample non english: آ Kilian à Dijon #4 • Vlog #2 • Primark again !? - YouTube Funfesty on Twitter: "Je commence à avoir mal à la tête à force Sia 2017 Cheap Thrills 2017 live lt;/textarea><br><input type="submit" id="submit" value="Remove Emojis"/><br><textarea id="after" cols="75" rows="5"></textarea>

How do I remove emoji from string

Karol S already provided a solution, but the reason might not be clear:

"\u1F600" is actually "\u1F60" followed by "0":

"\u1F60"    # => "ὠ"
"\u1F600"   # => "ὠ0"

You have to use curly braces for code points above FFFF:

"\u{1F600}" #=> "br>

Therefore the character class [\u1F600-\u1F6FF] is interpreted as [\u1F60 0-\u1F6F F], i.e. it
matches "\u1F60", the range "0".."\u1F6F" and "F".

Using curly braces solves the issue:

/[\u{1F600}-\u{1F6FF}]/

This matches (emoji) characters in these unicode blocks:

• U+1F600..U+1F64F Emoticons
• U+1F650..U+1F67F Ornamental Dingbats
• U+1F680..U+1F6FF Transport and Map Symbols

---

You can also use unpack, pack, and between? to achieve a similar result. This also works for Ruby 1.8.7 which doesn't support Unicode in regular expressions.

s = 'Hi!'
#=> "Hi!\360\237\230\200"

s.unpack('U*').reject{ |e| e.between?(0x1F600, 0x1F6FF) }.pack('U*')
#=> "Hi!" 

---

Regarding your Rubular example – Emoji are single characters:

".length  #=> 1
".chars   #=> ["]

Whereas kaomoji are a combination of multiple characters:

"^_^".length #=> 3
"^_^".chars  #=> ["^", "_", "^"]

Matching these is a very different task (and you should ask that in a separate question).

Need to remove emoji's and simple icons from input with javascript

You can use the opposite for your regex by doing:

'keyup': function() {
    this.value = this.value.replace(/[^\w.,\s]/g, '');
             Replace those that are not --^
             words, dots, comma, spaces...

And then add all the characters you want to allow in the character class. I left letters, _, ., , and spaces as valid but you can add what you consider valid.

Found these list of Polish characters:

Ą \u0104
Ć \u0106
Ę \u0118
Ł \u0141
Ń \u0143
Ó \u00D3
Ś \u015A
Ź \u0179
Ż \u017B
ą \u0105
ć \u0107
ę \u0119
ł \u0142
ń \u0144
ó \u00F3
ś \u015B
ź \u017A
ż \u017C

So, you can use this code which allows polish characters too:

'keyup': function() {
    this.value = this.value.replace(/[^\w.,\s\u0104\u0106\u0118\u0141\u0143\u00D3\u015A\u0179\u017B\u0105\u0107\u0119\u0142\u0144\u00F3\u015B\u017A\u017C]/gu, '');

Matching unicode with javascript might not be as straightforward as we think, so in this like you can check a deeper explanation.

A code sample about matching unicode with regex is:

/foo.bar/.test('foobar')
// false

/foo.bar/u.test('foobar')   // Notice the `u` (unicode flag)
// true

Update: as CLaFarge pointed in his comment if you need the unicode block for emoticons the range is 1F600-1F64F

Regex for entering letters without emojis

Your RegExp character set is incomplete as it doesn't include every Emoji. I got the full unicode character set of all 845 Emojis in existence from {another answer on Stack Overflow}

The inverse RegExp is unnecessary for this case, and yours didn't have the right syntax. Proper form: ^((?!••••••••••).)*$ as mentioned in {another answer on Stack Overflow}

Here's the new RegExp:

^[^\u{203C}\u{2049}\u{20E3}\u{2122}\u{2139}\u{2194}-\u{2199}\u{21A9}-\u{21AA}\u{231A}-\u{231B}\u{23E9}-\u{23EC}\u{23F0}\u{23F3}\u{24C2}\u{25AA}-\u{25AB}\u{25B6}\u{25C0}\u{25FB}-\u{25FE}\u{2600}-\u{2601}\u{260E}\u{2611}\u{2614}-\u{2615}\u{261D}\u{263A}\u{2648}-\u{2653}\u{2660}\u{2663}\u{2665}-\u{2666}\u{2668}\u{267B}\u{267F}\u{2693}\u{26A0}-\u{26A1}\u{26AA}-\u{26AB}\u{26BD}-\u{26BE}\u{26C4}-\u{26C5}\u{26CE}\u{26D4}\u{26EA}\u{26F2}-\u{26F3}\u{26F5}\u{26FA}\u{26FD}\u{2702}\u{2705}\u{2708}-\u{270C}\u{270F}\u{2712}\u{2714}\u{2716}\u{2728}\u{2733}-\u{2734}\u{2744}\u{2747}\u{274C}\u{274E}\u{2753}-\u{2755}\u{2757}\u{2764}\u{2795}-\u{2797}\u{27A1}\u{27B0}\u{2934}-\u{2935}\u{2B05}-\u{2B07}\u{2B1B}-\u{2B1C}\u{2B50}\u{2B55}\u{3030}\u{303D}\u{3297}\u{3299}\u{1F004}\u{1F0CF}\u{1F170}-\u{1F171}\u{1F17E}-\u{1F17F}\u{1F18E}\u{1F191}-\u{1F19A}\u{1F1E7}-\u{1F1EC}\u{1F1EE}-\u{1F1F0}\u{1F1F3}\u{1F1F5}\u{1F1F7}-\u{1F1FA}\u{1F201}-\u{1F202}\u{1F21A}\u{1F22F}\u{1F232}-\u{1F23A}\u{1F250}-\u{1F251}\u{1F300}-\u{1F320}\u{1F330}-\u{1F335}\u{1F337}-\u{1F37C}\u{1F380}-\u{1F393}\u{1F3A0}-\u{1F3C4}\u{1F3C6}-\u{1F3CA}\u{1F3E0}-\u{1F3F0}\u{1F400}-\u{1F43E}\u{1F440}\u{1F442}-\u{1F4F7}\u{1F4F9}-\u{1F4FC}\u{1F500}-\u{1F507}\u{1F509}-\u{1F53D}\u{1F550}-\u{1F567}\u{1F5FB}-\u{1F640}\u{1F645}-\u{1F64F}\u{1F680}-\u{1F68A}]*$

• ^ asserts position at the start of the string.

• [^••••••••••] is a negated character class. It matches every character that is NOT in the list, i.e. not an Emoji.

• * is a quantifier that matches any number of these non-Emoji characters.

• $ asserts position at the end of the string.

A working example of the RegExp inserted into <input pattern="">

<html><head>
    <meta charset="UTF-8">
</head><body>
    <form method="GET" action="javascript:console.log('VALID INPUT');">
        <input type="text" pattern="^[^\u{203C}\u{2049}\u{20E3}\u{2122}\u{2139}\u{2194}-\u{2199}\u{21A9}-\u{21AA}\u{231A}-\u{231B}\u{23E9}-\u{23EC}\u{23F0}\u{23F3}\u{24C2}\u{25AA}-\u{25AB}\u{25B6}\u{25C0}\u{25FB}-\u{25FE}\u{2600}-\u{2601}\u{260E}\u{2611}\u{2614}-\u{2615}\u{261D}\u{263A}\u{2648}-\u{2653}\u{2660}\u{2663}\u{2665}-\u{2666}\u{2668}\u{267B}\u{267F}\u{2693}\u{26A0}-\u{26A1}\u{26AA}-\u{26AB}\u{26BD}-\u{26BE}\u{26C4}-\u{26C5}\u{26CE}\u{26D4}\u{26EA}\u{26F2}-\u{26F3}\u{26F5}\u{26FA}\u{26FD}\u{2702}\u{2705}\u{2708}-\u{270C}\u{270F}\u{2712}\u{2714}\u{2716}\u{2728}\u{2733}-\u{2734}\u{2744}\u{2747}\u{274C}\u{274E}\u{2753}-\u{2755}\u{2757}\u{2764}\u{2795}-\u{2797}\u{27A1}\u{27B0}\u{2934}-\u{2935}\u{2B05}-\u{2B07}\u{2B1B}-\u{2B1C}\u{2B50}\u{2B55}\u{3030}\u{303D}\u{3297}\u{3299}\u{1F004}\u{1F0CF}\u{1F170}-\u{1F171}\u{1F17E}-\u{1F17F}\u{1F18E}\u{1F191}-\u{1F19A}\u{1F1E7}-\u{1F1EC}\u{1F1EE}-\u{1F1F0}\u{1F1F3}\u{1F1F5}\u{1F1F7}-\u{1F1FA}\u{1F201}-\u{1F202}\u{1F21A}\u{1F22F}\u{1F232}-\u{1F23A}\u{1F250}-\u{1F251}\u{1F300}-\u{1F320}\u{1F330}-\u{1F335}\u{1F337}-\u{1F37C}\u{1F380}-\u{1F393}\u{1F3A0}-\u{1F3C4}\u{1F3C6}-\u{1F3CA}\u{1F3E0}-\u{1F3F0}\u{1F400}-\u{1F43E}\u{1F440}\u{1F442}-\u{1F4F7}\u{1F4F9}-\u{1F4FC}\u{1F500}-\u{1F507}\u{1F509}-\u{1F53D}\u{1F550}-\u{1F567}\u{1F5FB}-\u{1F640}\u{1F645}-\u{1F64F}\u{1F680}-\u{1F68A}]*$">
        <input type="submit" value="Submit">
    </form>
<body></html>

Remove ✅, 🔥, ✈ , ♛ and other such emojis/images/signs from Java strings

Instead of blacklisting some elements, how about creating a whitelist of the characters you do wish to keep? This way you don't need to worry about every new emoji being added.

String characterFilter = "[^\\p{L}\\p{M}\\p{N}\\p{P}\\p{Z}\\p{Cf}\\p{Cs}\\s]";
String emotionless = aString.replaceAll(characterFilter,"");

So:

• [\\p{L}\\p{M}\\p{N}\\p{P}\\p{Z}\\p{Cf}\\p{Cs}\\s] is a range representing all numeric (\\p{N}), letter (\\p{L}), mark (\\p{M}), punctuation (\\p{P}), whitespace/separator (\\p{Z}), other formatting (\\p{Cf}) and other characters above U+FFFF in Unicode (\\p{Cs}), and newline (\\s) characters. \\p{L} specifically includes the characters from other alphabets such as Cyrillic, Latin, Kanji, etc.
• The ^ in the regex character set negates the match.

Example:

String str = "hello world _# 皆さん、こんにちは！　私はジョンと申します。;
System.out.print(str.replaceAll("[^\\p{L}\\p{M}\\p{N}\\p{P}\\p{Z}\\p{Cf}\\p{Cs}\\s]",""));
// Output:
//   "hello world _# 皆さん、こんにちは！　私はジョンと申します。"

If you need more information, check out the Java documentation for regexes.

HTML & Javascript |iOS| - Remove/Exclude emojis

I don't think it's possible to remove functionality from devices.

However someone has asked this question before and an answer has been given.
https://stackoverflow.com/a/10999907/4053708

Hope this helps you out as well.

How to remove only one user's reaction from an emoji

I found something that works:

reaction.message.reactions.cache.first() // fetch the reaction (you could use `.get()` as well)
  .users.remove(user.id); // remove the user

---

I'm really stumped as to why this works but my original function does not.

---

Edit: I'm an idiot. I was supposed to use the users property. reaction.users.remove() works fine.

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